When propanol is heated with `AI_(2)O_(3)` at `380^(@)C` (633K), the product obtained is:

Options

A. Dipropyl ether
B. Propene
C. Ethene
D. Diethyl ether

Explanation

To solve the question of what product is obtained when propanol is heated with Al2O3 at 380°C, we can follow these steps:

### Step 1: Understand the Reactants
Propanol is an alcohol with the chemical formula \( \text{C}_3\text{H}_8\text{O} \) or \( \text{CH}_3\text{CH}_2\text{CH}_2\text{OH} \).

### Step 2: Identify the Reaction Conditions
The reaction is performed at a high temperature (380°C or 633K) in the presence of a catalyst, which in this case is aluminum oxide (\( \text{Al}_2\text{O}_3 \)).

### Step 3: Determine the Type of Reaction
When alcohols are heated in the presence of a catalyst like \( \text{Al}_2\text{O}_3 \), they typically undergo dehydration. This means that water (\( \text{H}_2\text{O} \)) is removed from the alcohol.

### Step 4: Write the Dehydration Reaction
For propanol, the dehydration reaction can be represented as:
\[ \text{C}_3\text{H}_8\text{O} \rightarrow \text{C}_3\text{H}_6 + \text{H}_2\text{O} \]
Here, \( \text{C}_3\text{H}_6 \) is propene, which is the alkene product formed after the elimination of water.

### Step 5: Identify the Product
The product obtained from the dehydration of propanol is propene (\( \text{C}_3\text{H}_6 \)), which has the structure \( \text{CH}_3\text{CH}=\text{CH}_2 \).

### Conclusion
Therefore, when propanol is heated with \( \text{Al}_2\text{O}_3 \) at 380°C, the product obtained is propene.

### Final Answer
The correct option for the given question is propene.

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