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Assertion (A): Reaction between (Me(3)CO...

Assertion `(A)`: Reaction between `(Me_(3)CONa)` (sodium ter-butoxide) and ethyliode `(C_(2)H_(5)I)` does not produce an ether.
Reason `(R): Sodium ter-butoxide is a very strong base but is not a nucleophile.

A

Both `(A)` and `(R)` are true and `(R0` is the correct explanation of `(A)`.

B

Both `(A)` and `(R)` are true but `(R)` is not the correct explanation of `(A)`.

C

`(A) is true but `(R)` is false.

D

`(A) is false but `(R)` is true.

Text Solution

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The correct Answer is:
To solve the question, we need to analyze the assertion and reason provided: ### Assertion (A): The reaction between sodium tert-butoxide (Me₃CONa) and ethyl iodide (C₂H₅I) does not produce an ether. ### Reason (R): Sodium tert-butoxide is a very strong base but is not a nucleophile. ### Step-by-Step Solution: 1. **Understanding Sodium Tert-Butoxide**: - Sodium tert-butoxide (Me₃CONa) is a strong base due to the presence of the tert-butyl group (Me₃C). The tert-butyl group is bulky and has three methyl groups attached to the central carbon atom. 2. **Nature of the Reaction**: - When sodium tert-butoxide reacts with ethyl iodide (C₂H₅I), we need to consider the possible reaction pathways: nucleophilic substitution (SN2) and elimination (E2). 3. **Steric Hindrance**: - The bulky nature of sodium tert-butoxide means it has high steric hindrance. This steric hindrance makes it difficult for the base to act as a nucleophile in an SN2 reaction, where a nucleophile must approach the electrophilic carbon atom from the backside. 4. **Nucleophilic Substitution vs. Elimination**: - Due to the steric hindrance, the reaction will not proceed via the SN2 mechanism. Instead, it will proceed via an E2 elimination mechanism, where a hydrogen atom and the leaving group (iodine) are removed, forming an alkene. 5. **Product Formation**: - The product of the E2 reaction will be ethene (C₂H₄), not an ether. Therefore, the assertion is correct: the reaction does not produce an ether. 6. **Evaluating the Reason**: - The reason states that sodium tert-butoxide is a very strong base but not a nucleophile. This is true because its bulky structure prevents it from effectively attacking the electrophilic carbon in the alkyl halide. 7. **Conclusion**: - Both the assertion and reason are correct, and the reason correctly explains why the assertion is true. ### Final Answer: Both the assertion and reason are correct, and the reason is the correct explanation of the assertion.
To solve the question, we need to analyze the assertion and reason provided: ### Assertion (A): The reaction between sodium tert-butoxide (Me₃CONa) and ethyl iodide (C₂H₅I) does not produce an ether. ### Reason (R): Sodium tert-butoxide is a very strong base but is not a nucleophile. ...
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