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K(sp) of AgCl in water at 25^(@)C is 1.8...

`K_(sp)` of AgCl in water at `25^(@)C` is `1.8xx10^(-10)`. If `10^(-5)` mole of `Ag^(+)` ions are added to this solution. `K_(sp)` will be:

A

`1.8 xx 10^(-15)`

B

`1.8 xx 10^(-10)`

C

`1.8 xx 10^(-5)`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
B
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Knowledge Check

  • K _(sp) of AgCl at 18^(@) C is 1.8 xx 10 ^(-10) . If Ag ^(+) of solution is 4 xx 10 ^(-3) mollitre, the C ^(-) that must exceed before AgCl is precipated would be :

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    B
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    `1.8 xx 10^(-11)M`
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    `9.0 xx 10^(-10)M`
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    `6.5 xx 10^(12)M`
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  • What is the K_(sp) of AgCl if it is given that solubility of AgCl at 20^(@)C is 1.435xx10^(-5)g//L ?

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