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Let [epsilon0] denote the dimensional fo...

Let `[epsilon_0]` denote the dimensional formula of the permittivity of vacuum . If M = mass,L= length, T = time and A = electric current,then

A

`[epsilon_0] = [M^-1 L^-3T^2A]`

B

`[epsilon_0] = [M^-1 L^-3T^4A^2]`

C

`[epsilon_0] = [M^-2 L^2T^-1A^-2]`

D

`[epsilon_0] = [M^-1 L^2T^-1A^2]`

Text Solution

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The correct Answer is:
B
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