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A drop of solution (volume=0.05 ml) cont...

A drop of solution (volume=0.05 ml) contains 6 x `10^-7` mol of `H^+`. If the rate of disappearance of `H^+` is 6.0`xx 10^5` mol `L^-1 s^-1`, how long will it take for the `H^+` in the drop to disappear?

A

`8.0xx10^-8 s`

B

`2.0xx10^-8 s`

C

`6.0xx10^-6 s`

D

`2.0xx10^-2 s`

Text Solution

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The correct Answer is:
B
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Knowledge Check

  • A reaction , 2Ararr product , follows a zero order kinetics. If the rate constant of the reaction is 4.0xx10^(-4)"mol.L"^(-1).s^(-1) , then the rate of disappearance of A is -

    A
    `4.0xx10^(-4)"mol.L"^(-1).s^(-1)`
    B
    `2.0xx10^(-4)"mol.L"^(-1).s^(-1)`
    C
    `8.0xx10^(-4)"mol.L"^(-1).s^(-1)`
    D
    `1.2xx10^(-3)"mol.L"^(-1).s^(-1)`

  • In the reaction , A(g)rarr2B(g)+(1)/(2) C(g) , rate of formation of C is 10^(-3)"mol.L"^(-1).s^(-1) . Therefore , rate of disappearance ("in mol.L"^(-1).s^(-1)) of A and rate of formation ("in mol.L"^(-1).s^(-1)) of B , respectively , are -

    A
    `2.5xx10^(-3),5.0xx10^(-3)`
    B
    `2.0xx10^(-3),4.0xx10^(-3)`
    C
    `3.1xx10^(-2),6.2xx10^(-2)`
    D
    `1.0xx10^(-3),0.5xx10^(-3)`

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