Home
Class 12
PHYSICS
A parallel-plate capacitor is to be desi...

A parallel-plate capacitor is to be designed with a voltage rating of 1 kV using a material of dielectric constant 3 and dielectric strength about `10^7V//m`. For safety, we would like the field never to exceed (say) `10%` of the dielectric strength. What minimum area of the plates is required to have a capacitance `50muF` ?

Answer

Step by step text solution for A parallel-plate capacitor is to be designed with a voltage rating of 1 kV using a material of dielectric constant 3 and dielectric strength about 10^7V//m. For safety, we would like the field never to exceed (say) 10% of the dielectric strength. What minimum area of the plates is required to have a capacitance 50muF ? by PHYSICS experts to help you in doubts & scoring excellent marks in Class 12 exams.

Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • ELECTROSTATIC POTENTIAL AND CAPACITANCE

    PATHFINDER|Exercise QUESTION BANK|50 Videos

  • MAGNETIC EFFECT OF CURRENT AND ELECTROMAGNETISM-I,II AND III

    PATHFINDER|Exercise QUESTION BANK|213 Videos

Similar Questions

Explore conceptually related problems

A parallel plate capacitor is to be designed with a voltage rating 1 kV, using a material of dielectric constant 3 and dielectric strength about 10^(7) Vm^(-1) . (Dielectric strength is the maximum electric field a material can tolerate without breakdown, i.e., without starting to conduct electricity through partial ionisation.) For safety, we should like the field never to exceed, say 10% of the dielectric strength. What minimum area of the plates is required to have a capacitance of 50 pF?

The area of a parallel plate capacitor is 1 m^2 and the separation between its two plates is 10^(-4)m . The intermediate space is filled with a material of dielectric constant 7. A certain amount of charge raises its potential to 300 V. Determine the energy stored in the capacitor.

Knowledge Check

  • A parallel plate capacitor is to be designed, using a dielectric of dielectric constant 5, so as to have a dielectric strength of 10^(9)V*m^(-1) . If the voltage rating of the capacitor is 12kV, the minimum area of each plate required to have a capacitance of 80pF is

    A
    `10.5xx10^(-6)m^2`
    B
    `21.7xx10^(-6)m^2`
    C
    `25.0xx10^(-5)m^2`
    D
    `12.5xx10^(-5)m^2`

  • A parallel plate capacitor of capacitance 90 pF is connected to a battery of emf 20V. If a dielectric material of dielectric constant k=(5)/(3) is inserted between the plates, the magnitude of the induced charge will be

    A
    2.4 nC
    B
    0.9 nC
    C
    1.2 nC
    D
    0.3 nC

  • A parallel plate capacitor is made of two circular plates separated by a distance of 5mm and with a dielectric of dielectric constant 2.2 between them. When the electric field in the dielectric is 3xx10^(4) V/m , the charge density of the positive plate will be close to

    A
    `6xx10^(4) C/m^2`
    B
    `6xx10^(-7)C/m^2`
    C
    `3xx10^(-7)C/m^2`
    D
    `3xx10^(4)C/m^2`

    • Similar Questions

    Explore conceptually related problems

    A parallel plate capacitor has plates A and B each of area 0.5m^2 and a plate separation of 0.2 m. A dielectric slab of thickness 0.1m and dielectric constant 2.5 is placed between the two plates as shown - (a) FInd the capacitance of the capacitor, if the surface charge densities of the two plates are 8.854xx10^(-10)Cm^(-2) . (b) Graphically represent the variation of electric field between the two plates from A to B.

    Two parallel plate capacitors of capacitances C and 2C are connected in parallel and charged to a potential difference V. The battery is then disconnected and the region between the plates of the capacitor C is completely filled with a material of dielectric constant k. What is the potential difference across the capacitors now?

    The distance between the two plates of a parallel plate air capacitor is 3mm, and the radius of earch plate is 9 cm. It is given a charge of 10^(-7)C with a battery. Determine the energy stored in the capacitor. What will be the values of energy stored if a slab of dielectric constant 4 is introduced between the two plates Keeping the battery connected

    The distance between the two plates of a parallel plate air capacitor is 3mm, and the radius of earch plate is 9 cm. It is given a charge of 10^(-7)C with a battery. Determine the energy stored in the capacitor. What will be the values of energy stored if a slab of dielectric constant 4 is introduced between the two plates After removing the battery?

    A parallel-plate capacitor of area A, plate separation d and capacitance C is filled with four dielectric materials having dielectric constants k_1,k_2,k_3 and k_4 as shown in the figure below. If a single dielectric material is to be used to have the same capacitance C in this capacitor, then its dielectric constant k is given by

    Home
    Profile