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Mention the charge, mass and e/m ratio f...

Mention the charge, mass and e/m ratio for an electron.

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To answer the question regarding the charge, mass, and e/m ratio for an electron, we will break down the solution into clear steps. ### Step-by-Step Solution 1. **Charge of an Electron**: - The charge of an electron is negative. - The value of the charge is represented as \(-e\). - The magnitude of the charge is \(e = 1.6 \times 10^{-19}\) coulombs. - Therefore, the charge of an electron is: \[ \text{Charge of electron} = -1.6 \times 10^{-19} \text{ C} \] 2. **Mass of an Electron**: - The mass of an electron is a known constant. - It is given as: \[ \text{Mass of electron} = 9.1 \times 10^{-31} \text{ kg} \] 3. **E/M Ratio for an Electron**: - The e/m ratio (charge-to-mass ratio) is calculated using the formula: \[ \frac{e}{m} = \frac{\text{Charge}}{\text{Mass}} \] - Substituting the values we have: \[ \frac{e}{m} = \frac{1.6 \times 10^{-19} \text{ C}}{9.1 \times 10^{-31} \text{ kg}} \] - Performing the calculation: \[ \frac{e}{m} \approx 1.758 \times 10^{11} \text{ C/kg} \] - Therefore, the e/m ratio for an electron is approximately: \[ \frac{e}{m} \approx 1.758 \times 10^{11} \text{ C/kg} \] ### Summary of Results - **Charge of Electron**: \(-1.6 \times 10^{-19} \text{ C}\) - **Mass of Electron**: \(9.1 \times 10^{-31} \text{ kg}\) - **E/M Ratio**: \(1.758 \times 10^{11} \text{ C/kg}\)
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Knowledge Check

  • The ratio of charge to mass of an electron in coulombs per gram was determined by J.J. Thomson. He determined this ratio by measuring the deflection of cathode rays in electric and magnetic fields. What value did he find for this ratio?

    A
    `-1.76xx10^(8)` coulombs/g
    B
    `1.76xx10^(-8)` coulombs/g
    C
    `-1.76xx10^(10)` coulombs/g
    D
    `-1.76xx10^(-10)` coulombs/g
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