How many electrons are present in the atom whose electronic configuration is `1s^2, 2s^2, 2p_(x)^1?`

Answer

To determine the total number of electrons in the atom with the electronic configuration `1s^2, 2s^2, 2p_x^1`, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the electronic configuration**: The given electronic configuration is `1s^2, 2s^2, 2p_x^1`.

2. **Count the electrons in each subshell**:
- For the `1s` subshell: The notation `1s^2` indicates that there are 2 electrons in the `1s` subshell.
- For the `2s` subshell: The notation `2s^2` indicates that there are 2 electrons in the `2s` subshell.
- For the `2p` subshell: The notation `2p_x^1` indicates that there is 1 electron in the `2p_x` orbital.

3. **Add the electrons from each subshell**:
- Total electrons = Electrons in `1s` + Electrons in `2s` + Electrons in `2p_x`
- Total electrons = 2 (from `1s`) + 2 (from `2s`) + 1 (from `2p_x`)

4. **Calculate the total**:
- Total electrons = 2 + 2 + 1 = 5

5. **Conclusion**: The total number of electrons present in the atom is **5**.