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Which of the following molecule is of T ...

Which of the following molecule is of T -shape ?

A

`I_(3)^(-)`

B

`ClF_(3)`

C

`SF_(4)`

D

`XeF_(4)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which molecule is T-shaped, we need to analyze the molecular geometry of each option based on the number of bonding pairs and lone pairs around the central atom. Here’s a step-by-step breakdown: ### Step 1: Identify the Central Atom and Count Lone Pairs and Bonding Pairs For each molecule, identify the central atom and count the number of lone pairs and bonding pairs. 1. **I3- (Iodine triiodide ion)**: - Central atom: Iodine (I) - Lone pairs: 3 - Bond pairs: 2 2. **ClF3 (Chlorine trifluoride)**: - Central atom: Chlorine (Cl) - Lone pairs: 2 - Bond pairs: 3 3. **SF4 (Sulfur tetrafluoride)**: - Central atom: Sulfur (S) - Lone pairs: 1 - Bond pairs: 4 4. **XeF4 (Xenon tetrafluoride)**: - Central atom: Xenon (Xe) - Lone pairs: 2 - Bond pairs: 4 ### Step 2: Calculate the Steric Number The steric number is calculated as the sum of the number of bond pairs and lone pairs. - **I3-**: Steric number = 2 (bond pairs) + 3 (lone pairs) = 5 - **ClF3**: Steric number = 3 (bond pairs) + 2 (lone pairs) = 5 - **SF4**: Steric number = 4 (bond pairs) + 1 (lone pair) = 5 - **XeF4**: Steric number = 4 (bond pairs) + 2 (lone pairs) = 6 ### Step 3: Determine Hybridization Based on the steric number, we can determine the hybridization: - **I3-**: Steric number 5 → sp³d hybridization - **ClF3**: Steric number 5 → sp³d hybridization - **SF4**: Steric number 5 → sp³d hybridization - **XeF4**: Steric number 6 → sp³d² hybridization ### Step 4: Identify Molecular Geometry Using the VSEPR theory, we can predict the molecular geometry: - **I3-**: With 3 lone pairs in equatorial positions, the shape is linear (triangular bipyramidal geometry). - **ClF3**: With 2 lone pairs and 3 bond pairs, the shape is T-shaped (triangular bipyramidal geometry). - **SF4**: With 1 lone pair and 4 bond pairs, the shape is seesaw (triangular bipyramidal geometry). - **XeF4**: With 2 lone pairs and 4 bond pairs, the shape is square planar (octahedral geometry). ### Conclusion The molecule that is T-shaped is **ClF3**.
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AAKASH INSTITUTE ENGLISH-CHEMICAL BONDING AND MOLECULAR STRUCTURE -Assignment Section - B Objective Type Questions(One option is correct)
  1. The ion that is isoelectronic with CO is

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  2. CO(2) is isostructural with

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  3. When NH(3) is treated with HCl, H-N-H bond angle

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  4. Among KO2 , AlO(2)^(-) BaO2 and NO2^+ unpaired electron is present in...

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  5. Correct order of bond angle for O-P-X P{:(O),(/),( "\" ),(X):} in ...

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  6. Which of the following is non-linear ?

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  7. Which of the following is electron deficient (Lewis acid ) ?

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  8. In which of the following set of compounds , bond angle remains consta...

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  9. Which of the following compounds have zero dipole moment ?

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  10. Pick out the isoelectronic structures from the following (i) CH(3)^(...

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  11. The type of hybrid orbitals used by chlorine atom in ClO(2)^(-) is :

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  12. Which of the following molecule is of T -shape ?

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  13. The molecule which has pyramidal shape is

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  14. Which of the following compounds is non-polar ?

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  15. Polarization involves the distortion of the shape of an anion by an ad...

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  16. Arrange the given species in increasing order of O-O bond length und...

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  17. In which of the following , central atom does not have one lone pairs ...

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  18. In which conversion , bond length decreases ?

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  19. Which of the following combination of orbitals will form a nonbonding ...

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  20. Correct order for N-O bond length in the given species is underset(I...

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