STATEMENT-1 `KMnO_(4)` acts as powerful oxidising agent in acids, alkaline and neutral medium.
STATEMENT-2: Equivalent weight of `KMnO_(4)` in acidic medium in M/5 and in strongly alkaline medium in M/3.
STATEMENT-3 : `KMnO_(4)` solution is used as a primary standard and acts as self indicator during its titration more Mohr salt.

Options

A. T F T
B. F T T
C. F F T
D. F F F

Answer

To analyze the statements regarding KMnO₄, we will evaluate each statement step by step.

### Step 1: Evaluate Statement 1
**Statement 1:** KMnO₄ acts as a powerful oxidizing agent in acids, alkaline, and neutral medium.

- **Explanation:** KMnO₄ (Potassium permanganate) is known for its strong oxidizing properties. In acidic medium, it is reduced from MnO₄⁻ (where manganese has an oxidation state of +7) to Mn²⁺ (oxidation state +2) by gaining 5 electrons. In alkaline medium, it is reduced to MnO₄²⁻ (where manganese has an oxidation state of +6) by gaining only 1 electron. In neutral medium, it is reduced to MnO₂ (where manganese has an oxidation state of +4) by gaining 3 electrons. Thus, KMnO₄ acts as a powerful oxidizing agent in all three conditions.

- **Conclusion:** Statement 1 is **True**.

### Step 2: Evaluate Statement 2
**Statement 2:** The equivalent weight of KMnO₄ in acidic medium is M/5 and in strongly alkaline medium is M/3.

- **Explanation:** The equivalent weight of a substance is calculated using the formula:
\[ \text{Equivalent weight} = \frac{\text{Molar mass}}{n \text{ factor}} \]
In acidic medium, KMnO₄ gains 5 electrons (n factor = 5), so the equivalent weight is:
\[ \frac{M}{5} \]
In strongly alkaline medium, KMnO₄ gains only 1 electron (n factor = 1), so the equivalent weight is:
\[ \frac{M}{1} = M \]
Therefore, the statement that the equivalent weight in strongly alkaline medium is M/3 is incorrect.

- **Conclusion:** Statement 2 is **False**.

### Step 3: Evaluate Statement 3
**Statement 3:** KMnO₄ solution is used as a primary standard and acts as a self-indicator during its titration with Mohr salt.

- **Explanation:** KMnO₄ is stable and does not decompose at room temperature, making it suitable as a primary standard. During titration with Mohr salt (ferrous ammonium sulfate), KMnO₄ acts as a self-indicator. Initially, the solution is purple due to MnO₄⁻ ions. As the reaction proceeds and all MnO₄⁻ is reduced to Mn²⁺, the solution becomes colorless, indicating the endpoint of the titration.

- **Conclusion:** Statement 3 is **True**.

### Final Summary of Statements:
- Statement 1: True
- Statement 2: False
- Statement 3: True

### Final Answer:
The correct option is: **True, False, True**.

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