Calculate oxidation number of S in `S_4O_6^(2-)`.

Explanation

To calculate the oxidation number of sulfur (S) in the compound \( S_4O_6^{2-} \), we can follow these steps:

### Step 1: Assign oxidation states to oxygen
In most compounds, the oxidation state of oxygen is -2. However, in peroxides, it is -1. In \( S_4O_6^{2-} \), we have both types of oxygen.

### Step 2: Identify the structure
The structure of \( S_4O_6^{2-} \) includes:
- 6 oxygen atoms, where 2 are in a peroxide linkage (each contributing -1) and 4 are in the form of -2 oxidation state.
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