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For a unit cell of edge length 10 Å, ato...

For a unit cell of edge length 10 Å, atomic mass of that element is 150 g and density is `1 g cm^(-3)`.Find out the atomic radius .

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To find the atomic radius of the unit cell, we can follow these steps: ### Step 1: Understand the relationship between density, atomic mass, and the number of atoms in the unit cell. The formula relating density (ρ), atomic mass (m), number of atoms in the unit cell (Z), and the edge length (a) is given by: \[ \rho = \frac{Z \cdot m}{a^3 \cdot N_A} ...
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Knowledge Check

  • An element occurs in bcc structure. It has a cell edge length of 250 pm. Calculate the molar mass if its density is 8.0 g cm^(-3) . Also calculate the radius of an atom of this element.

    A
    109.25pm
    B
    108. 27 pm
    C
    208.24pm
    D
    108.25 pm
  • A bcc element (atomic mass 65) has a cell edge of 420 pm. Calculate its density in g/ cm^3

    A
    `2.25 g cm^(-3)`
    B
    `2.97 gcm^(-3)`
    C
    `2.84 g cm^(-3)`
    D
    `2.91 gcm^(-3)`
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