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The ion that cannot undergo disproportio...

The ion that cannot undergo disproportionation is :

A

`ClO_4 ^ (-)`

B

`ClO_3^(-)`

C

`ClO_2^(-)`

D

`ClO^(-)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding which ion cannot undergo disproportionation, we will follow these steps: ### Step 1: Understand Disproportionation Disproportionation is a specific type of redox reaction where a single substance is simultaneously oxidized and reduced, resulting in two different products. ### Step 2: Identify the Ions The ions given in the question are: - ClO4^- - ClO3^- - ClO2^- - ClO^- ### Step 3: Determine the Oxidation States We will calculate the oxidation state of chlorine in each ion. 1. **For ClO4^-**: - Let the oxidation state of Cl be \( x \). - The equation becomes: \( x + 4(-2) = -1 \) - Simplifying: \( x - 8 = -1 \) → \( x = +7 \) 2. **For ClO3^-**: - Let the oxidation state of Cl be \( x \). - The equation becomes: \( x + 3(-2) = -1 \) - Simplifying: \( x - 6 = -1 \) → \( x = +5 \) 3. **For ClO2^-**: - Let the oxidation state of Cl be \( x \). - The equation becomes: \( x + 2(-2) = -1 \) - Simplifying: \( x - 4 = -1 \) → \( x = +3 \) 4. **For ClO^-**: - Let the oxidation state of Cl be \( x \). - The equation becomes: \( x + (-2) = -1 \) - Simplifying: \( x - 2 = -1 \) → \( x = +1 \) ### Step 4: Analyze the Oxidation States Now, we analyze whether each ion can undergo disproportionation based on its oxidation states: - **ClO4^-**: Chlorine is in its highest oxidation state (+7). It cannot be oxidized further, so it cannot undergo disproportionation. - **ClO3^-**: Chlorine can be reduced (to +5) and oxidized (to +7), so it can undergo disproportionation. - **ClO2^-**: Chlorine can be reduced (to +3) and oxidized (to +5), so it can undergo disproportionation. - **ClO^-**: Chlorine can be reduced (to -1) and oxidized (to +1), so it can undergo disproportionation. ### Conclusion The ion that cannot undergo disproportionation is **ClO4^-**. ### Final Answer **ClO4^-**
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Knowledge Check

  • The Mn^(3+) ion is unstable in solution and undergoes disproportionation reaction to give Mn^(+2), MnO_(2) , and H^(o+) ion. Write a balanced ionic equation for the reaction.

    A
    `3Mn^(3+)+4H_(2)O rarr MnO_(2)+Mn^(2+)+8H^(+)`
    B
    `Mn^(2+)+4H_(2)O rarr MnO_(2) + 4H^(+)`
    C
    `Mn+2H_(2)O rarr MnO_(2) + 4H^(+)`
    D
    `2 M n^(3+)+2H_(2)O rarr MnO_(2)+Mn^(2+)+4H^(+)`
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