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Which of the following compounds have sa...

Which of the following compounds have same hybridisation?

A

`ClF_(3)`

B

`PF_(5)`

C

`XeF_(4)`

D

`SF_(4)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which compounds have the same hybridization, we will calculate the hybridization for each compound using the formula for steric number. The formula for hybridization is: \[ \text{Hybridization} = \frac{1}{2} \left( \text{Number of valence electrons of central atom} + \text{Number of monovalent atoms attached} + \text{Charge} \right) \] Let's analyze each compound step by step. ### Step 1: Calculate Hybridization of ClF3 - **Central Atom**: Chlorine (Cl) - **Valence Electrons of Cl**: 7 - **Monovalent Atoms Attached**: 3 (Fluorine atoms) - **Charge**: 0 (no charge) Using the formula: \[ \text{Hybridization} = \frac{1}{2} (7 + 3 + 0) = \frac{10}{2} = 5 \] - **Steric Number**: 5 - **Hybridization**: sp³d ### Step 2: Calculate Hybridization of PF5 - **Central Atom**: Phosphorus (P) - **Valence Electrons of P**: 5 - **Monovalent Atoms Attached**: 5 (Fluorine atoms) - **Charge**: 0 (no charge) Using the formula: \[ \text{Hybridization} = \frac{1}{2} (5 + 5 + 0) = \frac{10}{2} = 5 \] - **Steric Number**: 5 - **Hybridization**: sp³d ### Step 3: Calculate Hybridization of XeF4 - **Central Atom**: Xenon (Xe) - **Valence Electrons of Xe**: 8 - **Monovalent Atoms Attached**: 4 (Fluorine atoms) - **Charge**: 0 (no charge) Using the formula: \[ \text{Hybridization} = \frac{1}{2} (8 + 4 + 0) = \frac{12}{2} = 6 \] - **Steric Number**: 6 - **Hybridization**: sp³d² ### Step 4: Calculate Hybridization of SF4 - **Central Atom**: Sulfur (S) - **Valence Electrons of S**: 6 - **Monovalent Atoms Attached**: 4 (Fluorine atoms) - **Charge**: 0 (no charge) Using the formula: \[ \text{Hybridization} = \frac{1}{2} (6 + 4 + 0) = \frac{10}{2} = 5 \] - **Steric Number**: 5 - **Hybridization**: sp³d ### Conclusion From the calculations: - ClF3: sp³d - PF5: sp³d - XeF4: sp³d² - SF4: sp³d The compounds that have the same hybridization are **ClF3, PF5, and SF4**, all of which have sp³d hybridization.
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