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When 1 mole of anhydrous CuSO(4) is diss...

When 1 mole of anhydrous `CuSO_(4)` is dissolved in excess of water, -66.4 kJ heat is evolved. When one mole of `CuSO_(4).5H_(2)O` is dissolved in water, the heat change is +11.7 kJ. Calculate enthalpy of hydration of `CuSO_(4)` (anhydrous).

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To calculate the enthalpy of hydration of anhydrous CuSO₄, we can use the information provided about the heat changes when dissolving both anhydrous CuSO₄ and hydrated CuSO₄·5H₂O in water. ### Step-by-step Solution: 1. **Understanding the dissolution of CuSO₄:** - When 1 mole of anhydrous CuSO₄ is dissolved in water, the heat evolved is -66.4 kJ. This indicates that the process is exothermic. - When 1 mole of CuSO₄·5H₂O is dissolved, the heat change is +11.7 kJ, indicating that this process is endothermic. ...
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Knowledge Check

  • In CuSO_(4) · 5H_(2)O

    A
    all the five water molecules act as ligands
    B
    all the five `H_(2)O` molecules are attached to `Cu^(2 +)` ion
    C
    four `H_(2)O` molecules are coordinated to central `Cu^(2+)` ion while the fifth `H_(2)O` molecule is attached to `SO_(4)^(2-)` by hydrogen bonds
    D
    all the five water molecules occupy interstitial sites in the crystal lattice.
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