Statement-1: Phenol is more acidic than benzoic acid
Statement-2: Fluorbenzene is les reactive than chlorobenzene towards electrophilic substitiution
Statement-3: Friedel Craft alkylation is not possible in tertiary butyl benzene

Options

A. TFT
B. F F F
C. F T F
D. T T F

Answer

To analyze the statements provided in the question, we will evaluate each statement one by one.

### Step 1: Evaluate Statement 1
**Statement 1:** Phenol is more acidic than benzoic acid.

- **Explanation:**
- Phenol (C6H5OH) can release a proton (H+) to form a phenoxide ion (C6H5O-). The negative charge on the oxygen in the phenoxide ion is stabilized by resonance with the aromatic ring.
- Benzoic acid (C6H5COOH) can release a proton to form a benzoate ion (C6H5COO-). The negative charge on the benzoate ion is also stabilized by resonance, but it is further stabilized by the electronegative oxygen atom in the carboxylate group.
- The benzoate ion is more stable than the phenoxide ion due to the additional resonance stabilization provided by the carbonyl group (C=O) in benzoic acid.

- **Conclusion:** Benzoic acid is more acidic than phenol. Therefore, **Statement 1 is False.**

### Step 2: Evaluate Statement 2
**Statement 2:** Fluorobenzene is less reactive than chlorobenzene towards electrophilic substitution.

- **Explanation:**
- Electrophilic substitution reactions involve the attack of an electrophile on the aromatic ring.
- Fluorine is more electronegative than chlorine and has a strong +M (mesomeric) effect, which means it can donate electron density to the aromatic ring through resonance.
- However, fluorine also has a strong -I (inductive) effect, which withdraws electron density from the ring. The overall effect is that fluorobenzene is less reactive than chlorobenzene towards electrophilic substitution because the strong -I effect of fluorine outweighs its +M effect.

- **Conclusion:** Therefore, **Statement 2 is True.**

### Step 3: Evaluate Statement 3
**Statement 3:** Friedel-Craft alkylation is not possible in tertiary butyl benzene.

- **Explanation:**
- Friedel-Craft alkylation involves the formation of a carbocation, which then reacts with the aromatic ring.
- Tertiary butyl benzene (C6H5C(CH3)3) can form a tertiary butyl cation (C(CH3)3+) when treated with a Lewis acid like AlCl3.
- The tertiary butyl cation is stable and can effectively participate in Friedel-Craft alkylation.

- **Conclusion:** Therefore, **Statement 3 is False.**

### Final Summary of Statements:
- **Statement 1:** False
- **Statement 2:** True
- **Statement 3:** False