Home
Class 12
PHYSICS
A body of mas m starts from rest with a ...

A body of mas m starts from rest with a constant power. If velocity of the body at displacement s is v, then the correct alternative is

A

`s prop v`

B

`s propv^(2)`

C

`s propv^(3)`

D

`sprop v^(4)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to establish the relationship between the displacement \( s \) and the final velocity \( v \) of a body of mass \( m \) that starts from rest and moves with constant power \( P \). ### Step-by-Step Solution: 1. **Identify Given Data**: - Mass of the body: \( m \) - Initial velocity: \( u = 0 \) (starts from rest) - Displacement: \( s \) - Final velocity: \( v \) - Power: \( P \) (constant) 2. **Use the Power Formula**: The formula for power \( P \) is given by: \[ P = F \cdot v \] where \( F \) is the force acting on the body and \( v \) is its velocity. 3. **Express Force in Terms of Acceleration**: From Newton's second law, we know: \[ F = m \cdot a \] where \( a \) is the acceleration of the body. 4. **Relate Acceleration to Velocity and Displacement**: Using the third equation of motion: \[ v^2 = u^2 + 2as \] Since \( u = 0 \), this simplifies to: \[ v^2 = 2as \quad \Rightarrow \quad a = \frac{v^2}{2s} \] 5. **Substitute Acceleration into the Force Equation**: Now substituting \( a \) into the force equation: \[ F = m \cdot a = m \cdot \frac{v^2}{2s} = \frac{mv^2}{2s} \] 6. **Substitute Force into the Power Equation**: Now substituting \( F \) back into the power equation: \[ P = F \cdot v = \left(\frac{mv^2}{2s}\right) \cdot v = \frac{mv^3}{2s} \] 7. **Rearranging for Displacement**: Rearranging the equation gives: \[ P \cdot 2s = mv^3 \quad \Rightarrow \quad s = \frac{mv^3}{2P} \] 8. **Establishing the Relationship**: From the equation \( s = \frac{mv^3}{2P} \), we can see that: \[ s \propto v^3 \] This means that displacement \( s \) is directly proportional to the cube of the velocity \( v \). 9. **Conclusion**: The final relationship we derived is: \[ s \propto v^3 \] Therefore, we can conclude that the correct alternative is the one that states \( s \) is proportional to \( v^3 \).
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • WORK, ENERGY AND POWER

    AAKASH INSTITUTE ENGLISH|Exercise SECTION-C (OBJECTIVE TYPE QUESTIONS) (MORE THAN ONE OPTIONS ARE CORRECT)|16 Videos
  • WORK, ENERGY AND POWER

    AAKASH INSTITUTE ENGLISH|Exercise SECTION-D (LINKED COMPREHENSION TYPE QUESTIONS) (COMPREHENSION-I)|3 Videos
  • WORK, ENERGY AND POWER

    AAKASH INSTITUTE ENGLISH|Exercise SECTION-A (OBJECTIVE TYPE QUESTIONS (ONE OPTIONISCORRECT)|60 Videos
  • WAVES

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT ( SECTION-D ( Assertion - Reason Type Questions ))|12 Videos

Similar Questions

Explore conceptually related problems

A particle starts from rest and moves with constant acceleration. Then velocity displacement curve is:

A constant force actson a body of mass m, at rest and produces a velocity 'v' over a displacement ' s_1 '. The same force acts on another body of mass m_2 at rest and produces the same velocity. 'v' over a displacement ' s_2 '. The ratio of the displacements is

A body of mass m moving with a constant velocity v hits another body of the same mass moving with the same velocity v but in the opposite direction and sticks to it. The velocity of the compound body after collision is

A particle starts from rest with uniform acceleration a . Its velocity after 'n' second is 'v'. The displacement of the body in the last two second is

A body moves from rest with a uniform acceleration and travels 270 m in 3 s. Find the velocity of the body at 10 s after the start.

A body starts from rest and moves with constant acceleration. The ratio of distance covered by the body in nth second to that covered in n second is.

A body starts from rest, what is the ratio of the distance travelled by the body during the 4th and 3rd s?

At time t = 0, two bodies A and B at the same point. A moves with constant velocity upsilon and B starts from rest and moves with constant acceleration. Relative velocity of B w.r.t. A when the bodies meet each other is

A body starts from rest from a point distant r_(0) from the centre of the earth. It reaches the surface of the earth whose radius is R . The velocity acquired by the body is

A body starts from rest from a point distant r_(0) from the centre of the earth. It reaches the surface of the earth whose radius is R . The velocity acquired by the body is