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The value of C(V) for monatomic gas is (...

The value of `C_(V)` for monatomic gas is `(3)/(2)R`, then `C_(P)` will be

A

`(1)/(2)R`

B

`(7)/(2)R`

C

`(5)/(2)R`

D

`(3)/(2)R`

Text Solution

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The correct Answer is:
To find the value of \( C_P \) for a monatomic gas given that \( C_V = \frac{3}{2}R \), we can use Mayer's relation, which states: \[ C_P - C_V = R \] ### Step-by-Step Solution: 1. **Identify the given value of \( C_V \)**: - We know that \( C_V = \frac{3}{2}R \). 2. **Apply Mayer's relation**: - According to Mayer's relation, we have: \[ C_P = C_V + R \] 3. **Substitute the value of \( C_V \)**: - Substitute \( C_V = \frac{3}{2}R \) into the equation: \[ C_P = \frac{3}{2}R + R \] 4. **Convert \( R \) into a fraction with a common denominator**: - We can express \( R \) as \( \frac{2}{2}R \) to have a common denominator: \[ C_P = \frac{3}{2}R + \frac{2}{2}R \] 5. **Combine the fractions**: - Now, we can combine the two fractions: \[ C_P = \frac{3 + 2}{2}R = \frac{5}{2}R \] 6. **Final result**: - Thus, the value of \( C_P \) is: \[ C_P = \frac{5}{2}R \] ### Conclusion: The correct answer is \( C_P = \frac{5}{2}R \).
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