The temperature of a substance increases by `27^(@)C`. On the kelvin scale this increase is equal to

Options

A. 300K
B. 65 K
C. 27 K
D. 7 K

Answer

To find the increase in temperature on the Kelvin scale when the temperature of a substance increases by \(27^\circ C\), we can follow these steps:

### Step 1: Understand the relationship between Celsius and Kelvin
The relationship between the Celsius scale and the Kelvin scale is given by the formula:
\[ K = C + 273.15 \]
However, when calculating temperature changes (differences), the constant \(273.15\) does not affect the difference.

### Step 2: Recognize that temperature differences are equal
The change in temperature in Celsius (\(\Delta C\)) is equal to the change in temperature in Kelvin (\(\Delta K\)):
\[ \Delta C = \Delta K \]
This means that an increase of \(1^\circ C\) is equivalent to an increase of \(1 K\).

### Step 3: Apply the temperature change
Given that the temperature of the substance increases by \(27^\circ C\):
\[ \Delta C = 27^\circ C \]

### Step 4: Conclude the temperature change in Kelvin
Since \(\Delta C = \Delta K\):
\[ \Delta K = 27 K \]

Thus, the increase in temperature on the Kelvin scale is \(27 K\).

### Final Answer
The increase in temperature on the Kelvin scale is \(27 K\).

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