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Calculate magnetic field due to a bar ma...

Calculate magnetic field due to a bar magnet 2 cm long having pole strength 100 Am at a point 20 cm from centre of bar magnet .
(i) On axial point `" "` (ii) On normal bisector

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To solve the problem of calculating the magnetic field due to a bar magnet at a point 20 cm from its center, we will follow these steps for both the axial point and the normal bisector. ### Given Data: - Length of the bar magnet, \(2L = 2 \, \text{cm} = 2 \times 10^{-2} \, \text{m}\) - Pole strength, \(P = 100 \, \text{A m}\) - Distance from the center of the magnet to the point, \(R = 20 \, \text{cm} = 20 \times 10^{-2} \, \text{m}\) ### Step 1: Calculate the Magnetic Moment (M) ...
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A bar magnet is 0.10 m long and its pole strength is 120 Am . Find magnitude of magnetic field at a point on its axis at a distance 20 cm from it .

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Knowledge Check

  • What is the magnitude of axial field due to a bar magnet of length 3 cm at a distance of 75 cm from its mid-point if its magnetic moment is 0.6 Am^2 ?

    A
    0.013`mu` T
    B
    0.113 `mu` T
    C
    0.213 `mu` T
    D
    0.313 `mu` T
  • A short bar magnet has a magnetic moment of 0*48JT^-1 . Give the direction and magnitude of the magnetic field produced by the magnet at a distance of 10cm from the centre of the magnet on (i) the axis (ii) the equatorial line (normal bisector) of the magnet.

    A
    `0.48xx10^(-4)` T along N-S direction
    B
    `0.28xx10^(-4)` T along S-N direction
    C
    `0.28xx10^(-4)` T along N-S direction
    D
    `0.96xx10^(-4)` T along S-N direction
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