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Let ABCD be a parallelogram whose diagon...

Let `ABCD` be a parallelogram whose diagonals intersect at P and let O be the origin. Then prove that `vec(OA)+vec(OB)+vec(OC)+vec(OD)=4vec(OP)`.

A

`vecOP`

B

`2vecOP`

C

`3veOP`

D

`4vecOP`

Text Solution

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Knowledge Check

  • If ABCD is a rhombus whose diagonals intersect at E, then vec(EA) + vec(EB) + vec(EC) + vec( ED) equals

    A
    `vec(0)`
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    C
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