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In a young's doule slit experiment, wave...

In a young's doule slit experiment, wavelength of light used is `lambda`. Let O is the centre of line joining the slits and C is centre of screen where interference pattern is being obtained. `theta` is the angular position of each slit with respect to C and `phi` is angular position of first maxima with respect to O. select the correct alternative

A

a. Fringe width obtained is `(lambda theta)/2`

B

b. Fringe width obtained is `(lambda)/(2theta)`

C

c. The distance between the slits is `(lambda)/(phi)`

D

d. The distance between slits and screen is `(lambda)/(2 phi theta)`

Text Solution

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The correct Answer is:
B, C, D
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Knowledge Check

  • In a Young's double slit experiment, let S_(1) and S_(2) be the two slits, and C be the centre of the screen. If angle S_(1)CS_(2)=theta and lambda is the wavelength, the fringe width will be

    A
    `(lambda)/(theta)`
    B
    `lambda theta`
    C
    `(2lambda)/(theta)`
    D
    `(lambda)/(2theta)`

  • In young's double slit experiment using monochromatic light of wavelengths lambda , the intensity of light at a point on the screen with path difference lambda is M units. The intensity of light at a point where path difference is lambda//3 is

    A
    `(M)/(2)`
    B
    `(M)/(4)`
    C
    `(M)/(8)`
    D
    `(M)/(16)`

  • In a Young's double slit experiment, (slit distance d) monochromatic light of wavelength lambda is used and the fringe pattern observed at a distance D from the slits. The angular position of the bright fringes are

    A
    ` "sin"^(-1)((N lambda)/(d))`
    B
    ` "sin"^(-1)(((N+(1)/(2)) lambda)/(d))`
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    D
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