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In the binomial expansion of (a - b)^n ...

In the binomial expansion of `(a - b)^n , n ge 5 ` the sum of the 5th and 6th term is zero , then find `a/b`

A

`(n-5)/(6)`

B

`(n-4)/(5)`

C

`(5)/(n-4)`

D

`(-6)/(n-5)`

Text Solution

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The correct Answer is:
B
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In the binomial expansion of (a-b)^n,ngeq5, the sum of the 5th and 6th term is zero. Then a//b equals (n-5)//6 b. (n-4)//5 c. n//(n-4) d. 6//(n-5)

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Knowledge Check

  • In the binomial expansion of (a-b)^(n) , n ge 5 , the sum of 5th and 6th terms is zero, then (a)/(b) equals

    A
    (a) `(n-5)/(6)`
    B
    (b) `(n-4)/(5)`
    C
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    D
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  • In the binomial expansion of (1 + x)^(10) , the coefficeents of (2m + 1)^(th) and (4m + 5)^(th) terms are equal. Value of m is

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    -1
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    2
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