Home
Class 12
PHYSICS
The root-mean square speeds of the molec...

The root-mean square speeds of the molecules of different ideal gases, maintained at the same temperature are

A

The same

B

Inversely proportional to the square root of the molecular weight

C

Directly proportional to the molecular weight

D

Inversely proportional to the molecular weight

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the root-mean square (RMS) speeds of the molecules of different ideal gases maintained at the same temperature, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the RMS Speed Formula**: The root-mean square speed (v_rms) of gas molecules is given by the formula: \[ v_{rms} = \sqrt{\frac{3RT}{M}} \] where: - \( R \) is the universal gas constant, - \( T \) is the absolute temperature, - \( M \) is the molar mass (molecular weight) of the gas. 2. **Identify Constants**: Since the question states that the gases are maintained at the same temperature, \( T \) is constant for all gases. The gas constant \( R \) is also a constant. 3. **Analyze the Relationship**: From the formula, we can see that the RMS speed is inversely proportional to the square root of the molar mass: \[ v_{rms} \propto \frac{1}{\sqrt{M}} \] This means that as the molar mass \( M \) increases, the RMS speed \( v_{rms} \) decreases. 4. **Conclusion**: Therefore, we conclude that the root-mean square speeds of the molecules of different ideal gases, maintained at the same temperature, are inversely proportional to the square root of their molecular weights. 5. **Select the Correct Option**: Based on the analysis, the correct answer is that the RMS speeds are inversely proportional to the square root of the molecular weight, which corresponds to option number 2. ### Final Answer: The root-mean square speeds of the molecules of different ideal gases, maintained at the same temperature, are **inversely proportional to the square root of the molecular weight**. ---
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • KINETIC THEORY

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (Section-B) Objective type questions (One option is correct)|10 Videos
  • KINETIC THEORY

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (Section-C) Objective type questions (More than one option are correct)|9 Videos
  • KINETIC THEORY

    AAKASH INSTITUTE ENGLISH|Exercise Try Yourself|43 Videos
  • GRAVITATION

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT SECTION - D (ASSERTION-REASON TYPE QUESTIONS)|15 Videos
  • LAWS OF MOTION

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (SECTION-D) (Assertion-Reason Type Questions)|15 Videos

Similar Questions

Explore conceptually related problems

The root mean square speed of the molecules of a diatomic gas is v. When the temperature is doubled, the molecules dissociates into two atoms. The new root mean square speed of the atom is

The root mean square speed fo molecules of nitrogen gas is v at a certain temperature. When the temperature is doubled, the molecules dissociate into individual atoms. The new rms speed of the atom is:

Knowledge Check

  • The root mean square velocity of the gas molecule is 300 m/s. What will be the root mean square speed of he molecule if the atomic weight is doubled and absolute temperature is halved ?

    A
    300 m/s
    B
    150 m/s
    C
    600 m/s
    D
    75 m/s
  • Similar Questions

    Explore conceptually related problems

    The root mean square speed of the molecules of an enclosed gas is 'v'. What will be the root mean square speed if the pressure is doubled, the temperature remaining the same?

    The root mean square speed of N_(2) molecules in sample at temperature T is 'x'. If the temperature is doubled, then nitrogen molecules dissociate into atoms, the root mean square speedof nitrogen atoms becomes n times of 'x' find the value of n here?

    The root mean spuare (rms) speed of hydrogen molecules at a certain temperature is 300m/s. If the temperature is doubled and hydrogen gas dissociates into atomic hydrogen the rms speed will become

    The root mean square speed of the molecule at constant pressure at temperature T is v, what is its root mean square speed, if temperature is reduced to (T)/(2) .

    The root mean square speed of the molecule at constant pressure at temperature T is v, what is its rms speed, if temperature is reduced to (T)/(2)?

    The mean square speed of the molecules of a gas at absolute temperature T is proportional to

    The root-mean-square (rms) speed of oxygen molecules (O_(2)) at a certain absolute temperature is v.If the temperature is double and the oxygen gas dissociated into atomic oxygen, the rms speed would be