`10^(23)` electrons passed from left to rigth normally through a cross section in 1s. Average current through the cross section is

Options

A. `1.6 xx 10^(4) A`
B. `1.6 xx 10^(3) A`
C. `1.6 xx 10^(2) A`
D. ` 10^(23) A`

Answer

To find the average current through a cross section when \(10^{23}\) electrons pass through in 1 second, we can follow these steps:

### Step 1: Identify the given values
- Number of electrons, \( n = 10^{23} \)
- Time, \( t = 1 \) second

### Step 2: Calculate the total charge (Q)
The charge of a single electron is given by:
\[ e = 1.6 \times 10^{-19} \text{ coulombs} \]

The total charge \( Q \) can be calculated using the formula:
\[ Q = n \times e \]
Substituting the values:
\[ Q = 10^{23} \times 1.6 \times 10^{-19} \]

### Step 3: Perform the multiplication
Calculating the total charge:
\[ Q = 10^{23} \times 1.6 \times 10^{-19} = 1.6 \times 10^{4} \text{ coulombs} \]

### Step 4: Use the formula for current (I)
Current \( I \) is defined as the charge per unit time:
\[ I = \frac{Q}{t} \]
Substituting the values we have:
\[ I = \frac{1.6 \times 10^{4}}{1} \]

### Step 5: Calculate the average current
Thus, the average current is:
\[ I = 1.6 \times 10^{4} \text{ amperes} \]

### Final Answer
The average current through the cross section is \( 1.6 \times 10^{4} \) A.

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