Home
Class 12
PHYSICS
The electric field at 2R from the centr...

The electric field at 2R from the centre of a uniformly charged non - conducting sphere of rarius R is E. The electric field at a distance `( R )/(2)` from the centre will be

A

Zero

B

2E

C

4E

D

16E

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the electric field at a distance \( \frac{R}{2} \) from the center of a uniformly charged non-conducting sphere of radius \( R \), given that the electric field at a distance \( 2R \) from the center is \( E \). ### Step 1: Understand the electric field outside the sphere For a uniformly charged non-conducting sphere, the electric field outside the sphere (at a distance greater than \( R \)) is given by the formula: \[ E_{\text{outside}} = \frac{kQ}{r^2} \] where \( k \) is Coulomb's constant, \( Q \) is the total charge of the sphere, and \( r \) is the distance from the center of the sphere. ### Step 2: Apply the formula at \( 2R \) At a distance \( 2R \) from the center, we can substitute \( r = 2R \): \[ E = \frac{kQ}{(2R)^2} = \frac{kQ}{4R^2} \] ### Step 3: Understand the electric field inside the sphere For points inside the uniformly charged non-conducting sphere (at a distance less than \( R \)), the electric field is given by: \[ E_{\text{inside}} = \frac{kQ}{R^3} \cdot r \] where \( r \) is the distance from the center of the sphere. ### Step 4: Apply the formula at \( \frac{R}{2} \) Now, we need to find the electric field at a distance \( \frac{R}{2} \) from the center: \[ E_{\text{inside}} = \frac{kQ}{R^3} \cdot \left(\frac{R}{2}\right) = \frac{kQ}{R^3} \cdot \frac{R}{2} = \frac{kQ}{2R^2} \] ### Step 5: Relate the two electric fields We have two expressions for the electric field: 1. At \( 2R \): \( E = \frac{kQ}{4R^2} \) 2. At \( \frac{R}{2} \): \( E_{\frac{R}{2}} = \frac{kQ}{2R^2} \) ### Step 6: Find the ratio of the electric fields To find the relationship between \( E_{\frac{R}{2}} \) and \( E \): \[ \frac{E_{\frac{R}{2}}}{E} = \frac{\frac{kQ}{2R^2}}{\frac{kQ}{4R^2}} = \frac{2R^2}{4R^2} = \frac{2}{4} = \frac{1}{2} \] ### Step 7: Conclude the electric field at \( \frac{R}{2} \) Thus, we can express \( E_{\frac{R}{2}} \) in terms of \( E \): \[ E_{\frac{R}{2}} = \frac{1}{2} E \] ### Final Answer The electric field at a distance \( \frac{R}{2} \) from the center of the sphere is: \[ E_{\frac{R}{2}} = \frac{1}{2} E \]
Doubtnut Promotions Banner Mobile Dark
|

Similar Questions

Explore conceptually related problems

The electric field at a distance 3R//2 from the centre of a charge conducting spherical shell of radius R is E . The electric field at a distance R//2 from the centre of the sphere is

The electric field at a distance 3R//2 from the centre of a charge conducting spherical shell of radius R is E . The electric field at a distance R//2 from the centre of the sphere is

If the potential at the centre of a uniformly charged hollow sphere of radius R is V, then electric field at a distance r from the centre of sphere will be (rgtR) .

The electric field intensity at a distance 20 cm from the centre of a uniformly charged non conducting solid sphere of radius 10 cm is E .Then what is the electric field intensity at a distance 5 cm from the centre it will be.....

At a point 20 cm from the centre of a uniformly charged dielectric sphere of radius 10 cm , the electric field is 100 V//m . The electric field at 3 cm from the centre of the sphere will be

Find the electric field at the centre of a uniformly charged semicircular ring of radius R. Linear charge density is lamda

A conducting sphere of radius R is charged to a potential of V volts. Then the electric field at a distance r ( gt R) from the centre of the sphere would be

A hallow metal sphere of radius R is uniformly charged. The electric field due to the sphere at a distance r from the centre:

A solid non conducting sphere has charge density pCm^(-3) Electric field at distance x from its centre is ______ [x lt R]

Assertion: Electric potential on the surface of a charged sphere of radius R is V. Then electric field at distance r=R/2 from centre is V/(2R) . Charge is distributed uniformly over the volume. Reason: From centre to surface, electric field varies linearly with r. Here r is distance from centre.