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The de - Broglie wavelength of a particl...

The de - Broglie wavelength of a particle accelerated with `150 v_o` potential is `10^(-10) m`. If it is accelerated by `600 v_o`, its wavelength will be

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To solve the problem of finding the de Broglie wavelength of a particle when it is accelerated by a different potential, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the de Broglie Wavelength Formula**: The de Broglie wavelength (λ) of a particle is given by the formula: \[ \lambda = \frac{h}{\sqrt{2m e V}} ...
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Knowledge Check

  • The de Broglie wavelength lamda of an electron accelerated through a potential V in volts is

    A
    `(1.227)/(sqrt(V))nm`
    B
    `(0.1227)/(sqrt(V))nm`
    C
    `(0.01227)/(sqrt(V))nm`
    D
    `(12.27)/(sqrt(V))nm`
  • de Broglie wavelength of a moving particle is lambda . Its momentum is given by :

    A
    `(h lambda)/(c)`
    B
    `(h)/(lambda)`
    C
    `(hc)/(lambda)`
    D
    zero
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