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The charge to mass ratio of electron wa...

The charge to mass ratio of electron was found out to be

A

`1.6022xx10^(-19) kg^(-1)`

B

`1.925xx 10^(12) C kg^(-1)`

C

`1.758 xx 10^(11) C kg^(-1)`

D

`1.869 xx 10 ^(13 ) C kg ^(-1)`

Text Solution

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The correct Answer is:
To find the charge to mass ratio of an electron, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Charge of the Electron**: The charge of an electron (e) is known to be approximately: \[ e = 1.6 \times 10^{-19} \text{ coulombs} \] 2. **Identify the Mass of the Electron**: The mass of an electron (m) is approximately: \[ m = 9.1 \times 10^{-31} \text{ kilograms} \] 3. **Calculate the Charge to Mass Ratio**: The charge to mass ratio (e/m) can be calculated using the formula: \[ \frac{e}{m} = \frac{1.6 \times 10^{-19}}{9.1 \times 10^{-31}} \] 4. **Perform the Division**: Now, we perform the division: \[ \frac{1.6 \times 10^{-19}}{9.1 \times 10^{-31}} \approx 1.758 \times 10^{11} \text{ coulombs per kilogram} \] 5. **Express in Standard Form**: The result can be expressed as: \[ \frac{e}{m} \approx 1.758 \times 10^{11} \text{ C/kg} \] 6. **Final Result**: Therefore, the charge to mass ratio of the electron is: \[ \frac{e}{m} \approx 1.758 \times 10^{11} \text{ C/kg} \]
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Knowledge Check

  • The ratio of charge to mass of an electron in coulombs per gram was determined by J.J. Thomson. He determined this ratio by measuring the deflection of cathode rays in electric and magnetic fields. What value did he find for this ratio?

    A
    `-1.76xx10^(8)` coulombs/g
    B
    `1.76xx10^(-8)` coulombs/g
    C
    `-1.76xx10^(10)` coulombs/g
    D
    `-1.76xx10^(-10)` coulombs/g
  • The charge on an electron was calculated by

    A
    Faraday
    B
    J.J. Thomson
    C
    Millikan
    D
    Einstein
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