Which of the following compounds contains more than one kind of hybridized carbons?

Options

A. `CH_(2) = CH - CH = CH_(2)`
B. `H- C equiv C-H`
C. `CH_(3) CH_(2) CH_(2) CH_(3)`
D. `CH_(3)-CH = CH- CH_(3)`

Answer

To determine which of the given compounds contains more than one kind of hybridized carbon, we will analyze the hybridization of carbon atoms in each compound step by step.

### Step 1: Understand Hybridization
Hybridization is a concept used to explain the bonding in molecules. The type of hybridization can be determined by calculating the steric number, which is the sum of the number of sigma bonds and lone pairs around a carbon atom.

### Step 2: Identify the Compounds
Let’s assume we have four compounds to analyze (A, B, C, D). We will check the hybridization of carbon atoms in each compound.

### Step 3: Analyze Each Compound

#### Compound A:
1. **Identify Carbon Atoms**: Count the number of sigma bonds and lone pairs for each carbon.
2. **Calculate Steric Number**:
- For the first carbon: 4 sigma bonds (4 single bonds) → Steric number = 4 → Hybridization = sp³.
- For the second carbon: 3 sigma bonds + 1 pi bond (double bond) → Steric number = 3 → Hybridization = sp².
3. **Conclusion**: All carbons in Compound A are either sp³ or sp² hybridized.

#### Compound B:
1. **Identify Carbon Atoms**: Repeat the process for each carbon.
2. **Calculate Steric Number**:
- First carbon: 2 sigma bonds + 2 pi bonds (triple bond) → Steric number = 2 → Hybridization = sp.
- Second carbon: 2 sigma bonds + 2 pi bonds (triple bond) → Steric number = 2 → Hybridization = sp.
3. **Conclusion**: All carbons in Compound B are sp hybridized.

#### Compound C:
1. **Identify Carbon Atoms**: Analyze each carbon.
2. **Calculate Steric Number**:
- First carbon: 4 sigma bonds → Steric number = 4 → Hybridization = sp³.
- Second carbon: 3 sigma bonds + 1 pi bond → Steric number = 3 → Hybridization = sp².
3. **Conclusion**: Compound C contains both sp³ and sp² hybridized carbons.

#### Compound D:
1. **Identify Carbon Atoms**: Analyze each carbon.
2. **Calculate Steric Number**:
- First carbon: 4 sigma bonds → Steric number = 4 → Hybridization = sp³.
- Second carbon: 3 sigma bonds + 1 pi bond → Steric number = 3 → Hybridization = sp².
- Third carbon: 4 sigma bonds → Steric number = 4 → Hybridization = sp³.
3. **Conclusion**: Compound D contains both sp³ and sp² hybridized carbons.

### Step 4: Final Comparison
Now, we compare the hybridization types in each compound:
- Compound A: sp³, sp²
- Compound B: sp
- Compound C: sp³, sp²
- Compound D: sp³, sp²

### Step 5: Answer the Question
The compounds that contain more than one kind of hybridized carbon are:
- Compound A
- Compound C
- Compound D

However, if we are to select only one option that contains more than one kind of hybridized carbon, we can conclude that **Compound D** is the correct answer as it has both sp² and sp³ hybridized carbons.