Which compound has tetrachedral structure ?

Options

A. `XeF_(4)`
B. `XeOF_(2)`
C. `XeO_(2)F_(2)`
D. `XeO_(4)`

Answer

To determine which compound has a tetrahedral structure, we will analyze the given xenon compounds based on their hybridization and molecular geometry.

### Step-by-Step Solution:

1. **Identify the Compounds**: The compounds mentioned are:
- Xenon tetrafluoride (XeF4)
- Xenon dioxide (XeO2)
- Xenon oxyfluoride (XeOF2)
- Xenon tetrafluoride (XeF4)

2. **Determine Valence Electrons**:
- Xenon (Xe) has 8 valence electrons (as it is a noble gas).
- Each fluorine (F) atom contributes 1 valence electron.

3. **Analyze Each Compound**:
- **XeF4**:
- Valence electrons = 8 (Xe) + 4 (from 4 F) = 12 electrons.
- Bond pairs = 4 (from 4 F).
- Lone pairs = 2 (since 12 - 8 = 4 electrons, which means 2 lone pairs).
- Steric number = Bond pairs + Lone pairs = 4 + 2 = 6.
- Hybridization = sp3d2.
- Geometry = Square planar (not tetrahedral).

- **XeO2**:
- Valence electrons = 8 (Xe) + 2 (from 2 O) = 10 electrons.
- Bond pairs = 2 (from 2 O).
- Lone pairs = 3 (since 10 - 8 = 2 electrons, which means 2 lone pairs).
- Steric number = 2 + 3 = 5.
- Hybridization = sp3d.
- Geometry = Linear (not tetrahedral).

- **XeOF2**:
- Valence electrons = 8 (Xe) + 1 (from O) + 2 (from 2 F) = 11 electrons.
- Bond pairs = 3 (1 O and 2 F).
- Lone pairs = 2 (since 11 - 8 = 3 electrons, which means 2 lone pairs).
- Steric number = 3 + 2 = 5.
- Hybridization = sp3d.
- Geometry = T-shaped (not tetrahedral).

- **XeF4** (again):
- As analyzed, it has a square planar structure.

4. **Identify the Correct Compound**:
- The only compound that has a tetrahedral structure is **XeF4**, which has a steric number of 4 and hybridization of sp3.

### Conclusion:
The compound with a tetrahedral structure is **XeF4**.