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For an endothermic reaction to be sponta...

For an endothermic reaction to be spontaneous

A

`Delta G = 0`

B

`Delta G gt 0`

C

`Delta G lt 0`

D

`Delta G may be +ve or -ve`

Text Solution

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The correct Answer is:
To determine the conditions under which an endothermic reaction can be spontaneous, we need to analyze the relationship between Gibbs free energy (ΔG), enthalpy (ΔH), and entropy (ΔS). ### Step-by-Step Solution: 1. **Understanding Endothermic Reactions**: - An endothermic reaction is one that absorbs heat from the surroundings. This means that the change in enthalpy (ΔH) for the reaction is positive (ΔH > 0). 2. **Gibbs Free Energy Equation**: - The spontaneity of a reaction can be determined using the Gibbs free energy equation: \[ \Delta G = \Delta H - T \Delta S \] - Here, ΔG is the change in Gibbs free energy, ΔH is the change in enthalpy, T is the temperature in Kelvin, and ΔS is the change in entropy. 3. **Condition for Spontaneity**: - For a reaction to be spontaneous, ΔG must be less than 0 (ΔG < 0). - Rearranging the Gibbs free energy equation gives us: \[ \Delta G < 0 \implies \Delta H - T \Delta S < 0 \] - This can be rearranged to: \[ \Delta H < T \Delta S \] - This means that for an endothermic reaction (where ΔH is positive), the term \(T \Delta S\) must be greater than ΔH for the reaction to be spontaneous. 4. **Role of Entropy**: - Since ΔH is positive for endothermic reactions, we need a sufficiently high value of TΔS (where ΔS is the change in entropy) to ensure that the reaction can still be spontaneous. - Therefore, if ΔS is positive (indicating an increase in disorder), at high temperatures, the term \(T \Delta S\) can outweigh the positive ΔH, making ΔG negative. 5. **Conclusion**: - Thus, for an endothermic reaction to be spontaneous, it is necessary that ΔG < 0, which can occur when TΔS is sufficiently large to overcome the positive ΔH. ### Final Answer: The correct option is **C: ΔG < 0**.
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Knowledge Check

  • In endothermic reactions,

    A
    reactants have more energy than products
    B
    reactants have less energy than products
    C
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    D
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    A
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    B
    `DeltaH" is "-ve, DeltaS" is "+ve`
    C
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