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Oxidation number of Cr in CrO(5) is...

Oxidation number of Cr in `CrO_(5)` is

A

`+10`

B

`+6`

C

`+4`

D

`+5`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the oxidation number of chromium (Cr) in the compound CrO5, we can follow these steps: ### Step 1: Understand the structure of CrO5 CrO5 consists of one chromium atom and five oxygen atoms. The structure includes peroxy linkages (O-O bonds) and a direct bond to one oxygen atom. ### Step 2: Assign oxidation states to oxygen In CrO5, we have: - Four oxygen atoms are involved in peroxy linkages. Each of these oxygen atoms has an oxidation state of -1. - One oxygen atom is directly bonded to chromium and has a typical oxidation state of -2. ### Step 3: Set up the equation for oxidation states Let the oxidation number of chromium be \( x \). The total charge of the compound is neutral (0). Therefore, we can set up the equation based on the oxidation states: \[ x + (4 \times -1) + (-2) = 0 \] ### Step 4: Simplify the equation Now, simplify the equation: \[ x - 4 - 2 = 0 \] \[ x - 6 = 0 \] \[ x = +6 \] ### Conclusion The oxidation number of chromium (Cr) in CrO5 is +6. ---
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