Oxidation number of Cr in `CrO_(5)` is

Options

A. `+10`
B. `+6`
C. `+4`
D. `+5`

Answer

To determine the oxidation number of chromium (Cr) in the compound CrO5, we can follow these steps:

### Step 1: Understand the structure of CrO5
CrO5 consists of one chromium atom and five oxygen atoms. The structure includes peroxy linkages (O-O bonds) and a direct bond to one oxygen atom.

### Step 2: Assign oxidation states to oxygen
In CrO5, we have:
- Four oxygen atoms are involved in peroxy linkages. Each of these oxygen atoms has an oxidation state of -1.
- One oxygen atom is directly bonded to chromium and has a typical oxidation state of -2.

### Step 3: Set up the equation for oxidation states
Let the oxidation number of chromium be \( x \). The total charge of the compound is neutral (0). Therefore, we can set up the equation based on the oxidation states:

\[ x + (4 \times -1) + (-2) = 0 \]

### Step 4: Simplify the equation
Now, simplify the equation:

\[ x - 4 - 2 = 0 \]
\[ x - 6 = 0 \]
\[ x = +6 \]

### Conclusion
The oxidation number of chromium (Cr) in CrO5 is +6.

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