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In iodide of Million's base formed by th...

In iodide of Million's base formed by the reaction of Nessler's reagent with `NH_(3)`, the coordination number of Hg will be

A

2

B

3

C

4

D

6

Text Solution

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The correct Answer is:
To determine the coordination number of mercury (Hg) in the iodide of Million's base formed by the reaction of Nessler's reagent with ammonia (NH₃), we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Reaction**: The reaction involves Nessler's reagent, which is represented as \( K_2HgI_4 \), reacting with ammonia (\( NH_3 \)) and potassium hydroxide (\( KOH \)). The overall reaction can be summarized as: \[ 2K_2HgI_4 + 3KOH + NH_3 \rightarrow OHgHg(NH_3)I + 7KI + 2H_2O \] 2. **Identify the Product**: From the reaction, we can see that the product is a complex formed with mercury, ammonia, and iodide ions. The product can be represented as \( OHgHg(NH_3)I \). 3. **Determine the Coordination Number**: The coordination number refers to the number of ligand atoms that are bonded to the central metal atom (in this case, mercury). In the product \( OHgHg(NH_3)I \): - The \( NH_3 \) (ammonia) acts as a ligand and coordinates to mercury. - The iodide ion (I⁻) also coordinates to mercury. 4. **Count the Ligands**: In the complex: - There is 1 ammonia molecule coordinating to mercury. - There is 1 iodide ion coordinating to mercury. - Therefore, the total number of ligands coordinating to mercury is 2. 5. **Conclusion**: The coordination number of mercury (Hg) in the iodide of Million's base formed by the reaction of Nessler's reagent with ammonia is 2. ### Final Answer: The coordination number of Hg in the iodide of Million's base is **2**.
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