Home
Class 12
CHEMISTRY
underset("starch")(2(C6 H10 O5)(n)) + H2...

`underset("starch")(2(C_6 H_10 O_5)_(n)) + H_2 O overset("Distance")(to)n A overset(H_2 O)(to) 2n B`
A and B in given sequence of reactions, respectively is

A

Maltose, D-Glucose

B

Lactose, D-Glucose

C

Sucrose, D-Glucose

D

Maltose, fructose

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the hydrolysis of starch, we can break down the process step-by-step. ### Step-by-Step Solution: 1. **Identify the Reactant**: The reactant given is starch, which has the general formula \( (C_6H_{10}O_5)_n \). This indicates that starch is a polysaccharide made up of multiple units of the disaccharide. 2. **Hydrolysis of Starch**: When starch undergoes hydrolysis, it reacts with water (\( H_2O \)) in the presence of an enzyme. The enzyme that catalyzes the hydrolysis of starch is diastase. The reaction can be represented as: \[ (C_6H_{10}O_5)_n + n H_2O \xrightarrow{\text{diastase}} n \text{ maltose} \] Here, maltose is a disaccharide formed from the hydrolysis of starch. 3. **Formation of Maltose**: The product formed from the hydrolysis of starch is maltose. Therefore, in this step, we have: - A = Maltose (n moles of maltose). 4. **Further Hydrolysis of Maltose**: The maltose produced can undergo further hydrolysis in the presence of another enzyme called maltase. This reaction can be represented as: \[ n \text{ maltose} + n H_2O \xrightarrow{\text{maltase}} 2n \text{ glucose} \] Here, each maltose molecule is hydrolyzed to produce two glucose molecules. 5. **Formation of Glucose**: After the hydrolysis of maltose, we get glucose as the final product. Therefore, in this step, we have: - B = Glucose (2n moles of glucose). ### Conclusion: Thus, the respective products A and B in the given sequence of reactions are: - A = Maltose - B = Glucose ### Final Answer: A and B are Maltose and Glucose, respectively.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • BIOMOLECULES

    AAKASH INSTITUTE ENGLISH|Exercise EXERCISE (ASSIGNMENT) SECTION - C Previous Years Questions|25 Videos
  • BIOMOLECULES

    AAKASH INSTITUTE ENGLISH|Exercise EXERCISE (ASSIGNMENT) SECTION - C Previous Years Questions (Questions asked Prior to Medical Ent. Exams. 2005|33 Videos
  • BIOMOLECULES

    AAKASH INSTITUTE ENGLISH|Exercise EXERCISE (ASSIGNMENT) SECTION - A Objective Type Questions|50 Videos
  • AMINES

    AAKASH INSTITUTE ENGLISH|Exercise Assignment Section -J (Aakash Challengers Questions)|9 Videos
  • CHEMICAL BONDING AND MOLECULAR STRUCTURE

    AAKASH INSTITUTE ENGLISH|Exercise Assignment Section J (Aakash Challengers Questions)|10 Videos

Similar Questions

Explore conceptually related problems

C_(6)H_(5)N_(2)Cl overset(SnCl_(2)//HCl) (A) to overset(C_(6)H_(5)CHO)to(B) The product (B) in the above sequence of reaction is

C_6 H_5 N_2 Cl underset( " Pyridine ") overset ( Cu_2 (CN ) _2 ) to A overset( H_3 O^(+) ) to B . Here [B] is

Knowledge Check

  • H - C = C- H underset(H_2SO_4) overset(HgSO_4)to (A) underset((2) H_3O^(o+)) overset((1) NH_3 + HCN)to(B) , Product (B) of given reaction is :

    A
    Glycine
    B
    Alanine
    C
    valine
    D
    Leucine
  • For a reaction, 2NO + 2H_(2) to N_(2) + 2H_(2) O , the possible mechanism is NO hArr N_(2)O_(2) N_(2)O_(2) + H_(2) overset("Slow")(to) N_(2)O + H_(2) O N_(2) O + H_(2) O overset("fast")(to) N_(2) + H_(2) O What is the rate law and order of the reaction?

    A
    Rate = `[N_(2)O_(2)]`, order = 1
    B
    Rate = `[N_(2)O_(2)][H_(2)]`, order = 2
    C
    Rate = `[N_(2)O_(2)]^(2)` order = 2
    D
    Rate = `[N_(2)O_(2)]^(2) [H_(2)]`, order = 3
  • Similar Questions

    Explore conceptually related problems

    C_6 H_5 NH_2 underset(0^@ C) overset( NaNO_2 //HCI)to (A) overset(H_3 PO_2 // H_2 O ) to (B ) the compound (B ) is :

    H_(2)O_(2)+overset(Θ)(O)H B and C are:

    A+H_(2)Oto NaOH A underset(400^(@)C)overset(O_(2))rarrBunderset(at25^(@)C)overset(H_(2)O)rarrNaOH+O_(2), B is used for oxygenating in submarines A and B are respectively.

    A+H_(2)Oto NaOH A underset(400^(@)C)overset(O_(2))rarrBunderset(at25^(@)C)overset(H_(2)O)rarrNaOH+O_(2), B is used for oxygenating in submarines A and B are respectively.

    CH_3-C-=Noverset(H_2"O"//Delta)rarr(A)overset(H_2"O"//H^+)rarr(B)(A) and (B) respectively are

    Aniline underset( 50 ^@ C ) overset( H_2 O_2 ) to A ,[A] is :