Home
Class 12
CHEMISTRY
Which of the following is/are Dobereiner...

Which of the following is/are Dobereiner's triad?
(a) Li, Na, K
(b) Cu, Ag, Zn
(c) Fe, Co, Ni
(d) Ca, Sr, Ba Correct answer is

A

(a) & (b)

B

(a) & (d)

C

(b) & (c)

D

(a), (b), (c) & (d)

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the given sets of elements are Dobereiner's triads, we need to apply the concept introduced by Johann Wolfgang Döbereiner. According to his theory, a triad consists of three elements where the atomic weight of the middle element is approximately equal to the average of the atomic weights of the other two elements. Let's analyze each option step by step: ### Step 1: Analyze Option (a) Li, Na, K - Atomic masses: - Lithium (Li) = 7 - Sodium (Na) = 23 - Potassium (K) = 39 - Calculate the average of Li and K: \[ \text{Average} = \frac{7 + 39}{2} = \frac{46}{2} = 23 \] - Since the average atomic mass (23) is equal to the atomic mass of Sodium (Na), this set forms a Dobereiner's triad. ### Step 2: Analyze Option (b) Cu, Ag, Zn - Atomic masses: - Copper (Cu) = 63.5 - Silver (Ag) = 107.9 - Zinc (Zn) = 65.4 - Calculate the average of Cu and Zn: \[ \text{Average} = \frac{63.5 + 65.4}{2} = \frac{128.9}{2} = 64.45 \] - The average (64.45) is not close to the atomic mass of Silver (Ag = 107.9), so this set does not form a Dobereiner's triad. ### Step 3: Analyze Option (c) Fe, Co, Ni - Atomic masses: - Iron (Fe) = 55.8 - Cobalt (Co) = 58.9 - Nickel (Ni) = 58.7 - Calculate the average of Fe and Ni: \[ \text{Average} = \frac{55.8 + 58.7}{2} = \frac{114.5}{2} = 57.25 \] - The average (57.25) is not close to the atomic mass of Cobalt (Co = 58.9), so this set does not form a Dobereiner's triad. ### Step 4: Analyze Option (d) Ca, Sr, Ba - Atomic masses: - Calcium (Ca) = 40 - Strontium (Sr) = 87.6 - Barium (Ba) = 137 - Calculate the average of Ca and Ba: \[ \text{Average} = \frac{40 + 137}{2} = \frac{177}{2} = 88.5 \] - The average (88.5) is close to the atomic mass of Strontium (Sr = 87.6), so this set forms a Dobereiner's triad. ### Conclusion The sets that form Dobereiner's triads are: - (a) Li, Na, K - (d) Ca, Sr, Ba Thus, the correct answer is **(a) and (d)**.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • MOCK TEST 40

    AAKASH INSTITUTE ENGLISH|Exercise Example|30 Videos
  • MOCK TEST 6

    AAKASH INSTITUTE ENGLISH|Exercise Example|22 Videos

Similar Questions

Explore conceptually related problems

Which of the following substances are diamagnetic? Bi, Al, Na, Cu, Ca and Ni.

Which of the following are not representative elements ? Li, K, Al, Cu, Ne, Fe, S, Ce, Th

Knowledge Check

  • Which of the following sets belong to the same period ? Li, Na, K Li, Mg, Ca Cu, Ni, Zn F, Cl, Br.

    A
    Li, Na, K
    B
    Li, Mg, Ca
    C
    Cu, Ni, Zn
    D
    F, Cl, Br.
  • Which of the following is an amphoteric hydroxide? (a) Mg(OH)_2 (b) Be(OH)_2 (c) Sr(OH)_2 (d) Ca(OH)_2

    A
    `Mg(OH)_2`
    B
    `Be(OH)_2`
    C
    `Sr(OH)_2`
    D
    `Ca(OH)_2`
  • Similar Questions

    Explore conceptually related problems

    Can the following groups of elements be classified as Dobereiner's triad ? (a) Na, Si, Cl (b) Be, Mg, Ca Atomic mass of Be 9 , Na 23 , Mg 24 , Si 28 , Cl 35 , Ca 40 Explain by giving reason.

    Which one of the following transition metal ions is diamagnetic? Co^(2+) , Ni^(2+) , Cu^(2+) , Zn^(2+)

    For each of the following pairs which has greater IE and why? a. Li, Li^(o+) , b. K, Br , c. Br, I , d. Na^(o+) , Ne

    Which of the following sets of elements delays flowering if their concentration in plants is low? (a) N, K, Mg , S (b) N , S, P (c) Ca, Mg , Cu (d) N, S, Mo

    Fe can displace which of the following ions from their aqueous solutions? (a) Na^(+) (b) Zn^(2+) (c) Cu^(2+) (d) Ag^(+)

    Describe giving reason which one of the following pairs has the property indicated? (a). Fe or Cu has higher melting point. (b). Co^(2+) or Ni^(2+) has lower magnetic moment.