XeOF, contains

Options

A. Six electron pairs forming an octahedron with two positions occupied by lone pairs
B. Two pi-bonds and the remaining six electron pairs, forming an octahedron
C. Three pi-bonds and the remaining four electron pairs forming a tetrahedron
D. One T-bond and the remaining six electron pairs forming an octahedron with one position occupied by a lone pair

Answer

To determine the correct characteristics of the molecule XeOF4, we can follow these steps:

### Step 1: Identify the central atom and its valence electrons
- **Central Atom**: Xenon (Xe)
- **Valence Electrons of Xenon**: Xenon is a noble gas from group 18, with the electron configuration of [Kr] 5s² 5p⁶. Therefore, it has 8 valence electrons.

### Step 2: Identify the surrounding atoms and their contributions
- **Oxygen (O)**: Contributes 6 valence electrons.
- **Fluorine (F)**: Each fluorine atom contributes 7 valence electrons, and since there are 4 fluorine atoms, they contribute a total of 4 x 7 = 28 valence electrons.

### Step 3: Calculate the total number of valence electrons
- Total valence electrons = Valence electrons from Xe + Valence electrons from O + Valence electrons from 4 F
- Total = 8 (Xe) + 6 (O) + 28 (4 F) = 42 valence electrons.

### Step 4: Determine the number of bonding pairs and lone pairs
- **Bonds**: Xe forms 4 single bonds with the 4 fluorine atoms and 1 double bond with the oxygen atom.
- **Lone Pairs**: After forming 5 bonds (4 with F and 1 with O), there will be 1 lone pair left on the xenon atom.

### Step 5: Calculate the steric number
- **Steric Number** = Number of sigma bonds + Number of lone pairs
- Here, we have 4 sigma bonds (from F) + 1 sigma bond (from O) + 1 lone pair = 6.

### Step 6: Determine the hybridization
- The hybridization corresponding to a steric number of 6 is sp³d².

### Step 7: Determine the molecular geometry
- With a steric number of 6 and one lone pair, the molecular geometry is octahedral, with the lone pair occupying one of the positions.

### Conclusion
- The XeOF4 molecule has a hybridization of sp³d² and an octahedral geometry with one lone pair.

### Final Answer
- The correct statement about XeOF4 is: "It has 1 pi bond and the remaining 6 electron pairs forming an octahedron with one position occupied by a lone pair."