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When ClO3^-, changes toCI^-...

When `ClO_3^-`, changes to`CI^-`

A

It gains six electrons

B

It gains four electrons

C

It loses six electrons

D

It gains three electrons

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of how the chlorate ion \( \text{ClO}_3^- \) changes to the chloride ion \( \text{Cl}^- \), we need to analyze the change in the oxidation state of chlorine during this transformation. ### Step-by-Step Solution: 1. **Identify the oxidation state of chlorine in \( \text{ClO}_3^- \)**: - Let the oxidation state of chlorine be \( x \). - The oxidation state of oxygen is typically \( -2 \). - In \( \text{ClO}_3^- \), there are three oxygen atoms, contributing a total of \( 3 \times (-2) = -6 \). - The overall charge of the ion is \( -1 \). - Therefore, we can set up the equation: \[ x - 6 = -1 \] - Solving for \( x \): \[ x = -1 + 6 = +5 \] - Thus, the oxidation state of chlorine in \( \text{ClO}_3^- \) is \( +5 \). 2. **Identify the oxidation state of chlorine in \( \text{Cl}^- \)**: - In \( \text{Cl}^- \), the oxidation state of chlorine is \( -1 \). 3. **Determine the change in oxidation state**: - The change in oxidation state from \( +5 \) in \( \text{ClO}_3^- \) to \( -1 \) in \( \text{Cl}^- \) can be calculated as follows: \[ \text{Change} = \text{Final state} - \text{Initial state} = -1 - (+5) = -1 - 5 = -6 \] - This indicates that the chlorine atom has gained 6 electrons. 4. **Conclusion**: - Since the oxidation state of chlorine decreases from \( +5 \) to \( -1 \), it means that chlorine is being reduced. In reduction, a species gains electrons. - Therefore, \( \text{ClO}_3^- \) gains 6 electrons to become \( \text{Cl}^- \). ### Final Answer: The correct option is that \( \text{ClO}_3^- \) gains 6 electrons to become \( \text{Cl}^- \). ---
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