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Which of the following will not lead to ...

Which of the following will not lead to the formation of an alkyl halide?

A

`C_2H_5OHoverset("Red P+ Br_2)rarr`

B

`C_2H_5OHoverset("SoCl_2)rarr`

C

Both 1 and 2

D

None of these

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the given options will not lead to the formation of an alkyl halide, we need to analyze the reactions of the compounds provided in the options. An alkyl halide is a compound that contains an alkyl group (R) bonded to a halogen (X), represented as R-X. ### Step-by-Step Solution: 1. **Identify the Compounds**: The question mentions C2H5OH and reactions with red phosphorus (P) and bromine (Br2), as well as thionyl chloride (SOCl2). 2. **Reaction of C2H5OH with P and Br2**: - When C2H5OH (ethanol) reacts with red phosphorus and bromine, it forms phosphorus tribromide (PBr3). - The reaction proceeds as follows: - The lone pair on the oxygen of the alcohol attacks PBr3, leading to the formation of an intermediate. - Hydrogen is eliminated as HBr, and the bromine from PBr3 attaches to the ethyl group (C2H5). - The final product is C2H5Br (bromoethane), which is an alkyl halide. 3. **Reaction of C2H5OH with SOCl2**: - When C2H5OH reacts with thionyl chloride (SOCl2), the oxygen attacks the sulfur in SOCl2. - This leads to the elimination of HCl and the formation of an intermediate. - The chlorine from SOCl2 then attaches to the ethyl group. - The final product is C2H5Cl (chloroethane), which is also an alkyl halide. 4. **Conclusion**: - Both reactions lead to the formation of alkyl halides (C2H5Br and C2H5Cl). - Therefore, if the question is asking for a compound that does not lead to the formation of an alkyl halide, we must consider that both reactions provided do form alkyl halides. 5. **Final Answer**: Since both reactions lead to the formation of alkyl halides, the correct option is **D. None of these**.
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Knowledge Check

  • Which of the following leads to the formation of an alkyl halide ?

    A
    `C_(2)H_(5)OH overset("Red" P+Br_(2)) to `
    B
    `C_(2)H_(5)OH overset(SOCl_(2)) to`
    C
    `C_(2)H_(5)OH overset("KBr+ Conc. H_(2)SO_(4)) to`
    D
    All of these
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