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Reaction intermediate formed in the form...

Reaction intermediate formed in the formation of salicylaldehyde from phenol (Reimer-Tiemann reaction) is

A

Carbocation

B

Free radical

C

Carbanion

D

Carbene

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To solve the question regarding the reaction intermediate formed in the formation of salicylaldehyde from phenol (Reimer-Tiemann reaction), we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Reaction Context**: The Reimer-Tiemann reaction involves the conversion of phenol to salicylaldehyde using chloroform (CHCl3) in a basic medium (usually KOH). **Hint**: Familiarize yourself with the Reimer-Tiemann reaction and its purpose in organic synthesis. 2. **Identify the Reactants**: The main reactants in this reaction are phenol (C6H5OH) and chloroform (CHCl3). **Hint**: Recognize the structure of phenol and chloroform to understand how they interact. 3. **Mechanism Overview**: In the presence of a strong base (KOH), the hydroxide ion (OH-) abstracts an acidic hydrogen from chloroform, leading to the formation of a carbanion intermediate (CCl3-). **Hint**: Recall the role of strong bases in deprotonation reactions. 4. **Formation of the Reaction Intermediate**: The carbanion intermediate (CCl3-) then undergoes a rearrangement, losing one chlorine atom to form a dichlorocarbene (CCl2). This intermediate is crucial as it is highly reactive and can attack the aromatic ring of phenol. **Hint**: Understand how carbanions can rearrange to form more stable intermediates. 5. **Attack on Phenol**: The dichlorocarbene (CCl2) acts as an electrophile and attacks the ortho or para position of the phenol, leading to the formation of salicylaldehyde. **Hint**: Consider the electrophilic aromatic substitution mechanism when thinking about how the carbene interacts with phenol. 6. **Conclusion**: The reaction intermediate formed during the Reimer-Tiemann reaction is a dichlorocarbene (CCl2). **Hint**: Remember that the nature of the intermediate is key to understanding the overall reaction mechanism. ### Final Answer: The reaction intermediate formed in the formation of salicylaldehyde from phenol in the Reimer-Tiemann reaction is **dichlorocarbene (CCl2)**.
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Knowledge Check

  • Phenol gives Reimer Tiemann reaction with :

    A
    `CHCl_(3)`
    B
    `C Cl_(4)`
    C
    `CHCl_(3) and C Cl_(4)`
    D
    `C_(6)H_(5)CHCl`
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