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For the galvanic cell Mg(s)|Mg^(2+)(aq)|...

For the galvanic cell `Mg(s)|Mg^(2+)(aq)||Zn^(2+)(aq)|Zn(s)`,the standard free energy change is (`Given:E_((mg^(2+))/(mg))^@=`-2.36`V,E_((Zn^(2+))/(Zn))^@=`-0.76`V)`

A

`-1.6`F

B

`-3.2`F

C

`-4.8`F

D

`-`F

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For the galvanic cell: Zn(s) | Zn^(2+)(aq) (1.0 M) || Ni^(2+)(aq) (1.0 M) | Ni(s) , E_(cell)^o will be [Given E_((Zn^(2+)) /(Zn))^0 = -0.76 V , E_((Ni^(2+))/(Ni))^0= -0.25V ]

The standard Gibbs free energy change (in joule) for the given cell reaction is Mg(s) + Ni^(2+) to Mg^(2+)(aq) + Ni(s) (Given: E_((mg)^(2+)/(mg))^@ = - 2.36 V , E_((NI)^(2+)/(NI))^@ = -0.25 V,

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Compute the standard free energy chagne (DeltaG^(@)) for the process Zn^(2+)(aq)+2e^(-)rarrZn(s) : E^(@)Zn^(2+)=-0.76V

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Calculate the maximum work that can be obtained from the daniell call given below, Zn(s)|Zn^(2+)(aq)||Cu^(2+)(aq)|Cu(s) . Given that E_(Zn^(2+)//Zn)^(@)=-0.76V and E_(Cu^(2+)//Cu)^(@)=+0.34V .

At 25^(@)C temperature the cell potential of a given electrochemical cell is 1.92 V Mg(s)|Mg^(2+)(Aq)x M||Fe^(2+)(aq)0.01 M |Fe(s) Given E_(Mg//mg^(2+))(Aq)=2.37 v E_(Fe//Fe^(2+))^(@)(Aq)=0.45 V Find the value of x

For the cell Zn((s)) |ZN^(2+) ((aq)) || M^(X+)((aq))|M((s)) , different half cells and their standard electrode potentials are given below : If E_(ZN^(2+)|ZN^(@))= -0.76V , which cathode will give a maximum value of E_(cell)^(@) per electron transferred ?

(a) What type of a battery is the lead storage battery ? Write the anode and the cathode reactions and the overall occuring in a lead storage battery when current is drawn from it. (b) In the buttom cell, widely used in watches the following reaction take place Zn_((s)) + Ag_(2)O_((l)) rarr Zn^(2+)(aq) + 2Ag_((s)) + 2OH_((aq))^(-) . Determine E^(@) and DeltaG^(@) for the reaction. (given : E_(Ag^(+)//Ag)^(@) = +0.80 V , E_(Zn^(2+)//Zn)^(@) = - 0.76 V)

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