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Find the angle between the lines represe...

Find the angle between the lines represented by `2x^(2) + xy- 6y ^(2)+ 7y - 2 = 0.`

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The correct Answer is:
`alpha="cos"^(-1)((4)/(sqrt(65)))`
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Find the angle between the straight lines represented by 2x^(2)+5xy+2y^(2)-5x-7y+3=0

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Knowledge Check

  • The angle between the planes represented by 2x ^(2) - 6y ^(2) - 12 z^(2) + 18 yz + 2 zx + xy =0 is

    A
    `Cos ^(-1) ((-16)/(21))`
    B
    `Cos ^(-1) ((17)/(21))`
    C
    `Cos^(-1) ((19)/(21))`
    D
    `pi/2`

  • The distance between the two lines represented by 8x^(2) - 24 xy + 18 y^(2) - 6x + 9y - 5 = 0 is

    A
    `0`
    B
    `(3)/(4sqrt(13))`
    C
    `(6)/(sqrt(13))`
    D
    `(7)/(2sqrt(13))`

  • The angle between the lines represented by y^(2) sin^(2) theta - xy sin^(2) theta + x^(2) (cos^(2) theta - 1) = 0 , is

    A
    `(pi)/(3)`
    B
    `(pi)/(4)`
    C
    `(pi)/(6)`
    D
    `(pi)/(2)`

    • Similar Questions

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    If the bisectors of the angles of the lines represented by 3x^(2) - 4xy + 5y^(2) = 0 and 5x^(2) + 4xy + 3y^(2) = 0 are same , then the angle made by the lines represented by first with the second , is

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