Find, which of the following points lie on the line `x - 2y + 5 = 0 ` : 
`(i) (1, 3) "    " (ii) (0,5)`
`(iii) (-5, 0) "    "  (iv) (5,5) `
`(v) (2, -1.5)"     "(-2, -1.5)`

Answer

To determine which points lie on the line given by the equation \( x - 2y + 5 = 0 \), we will substitute each point into the equation and check if the equation holds true (i.e., equals zero).

### Step-by-Step Solution:

1. **Rearranging the Equation**:
The equation of the line is given as:
\[ x - 2y + 5 = 0 \]
We can rearrange it to:
\[ x - 2y = -5 \]

2. **Testing Each Point**:
We will test each point by substituting the \( x \) and \( y \) values into the equation.

**Point (1, 3)**:
\[ 1 - 2(3) + 5 = 1 - 6 + 5 = 0 \]
This point lies on the line.

**Point (0, 5)**:
\[ 0 - 2(5) + 5 = 0 - 10 + 5 = -5 \]
This point does not lie on the line.

**Point (-5, 0)**:
\[ -5 - 2(0) + 5 = -5 + 0 + 5 = 0 \]
This point lies on the line.

**Point (5, 5)**:
\[ 5 - 2(5) + 5 = 5 - 10 + 5 = 0 \]
This point lies on the line.

**Point (2, -1.5)**:
\[ 2 - 2(-1.5) + 5 = 2 + 3 + 5 = 10 \]
This point does not lie on the line.

**Point (-2, -1.5)**:
\[ -2 - 2(-1.5) + 5 = -2 + 3 + 5 = 6 \]
This point does not lie on the line.

3. **Summary of Points**:
The points that lie on the line \( x - 2y + 5 = 0 \) are:
- (1, 3)
- (-5, 0)
- (5, 5)

### Final Answer:
The points that lie on the line are **(1, 3), (-5, 0), and (5, 5)**.