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{:(" 3A"),("+25"),(--),(" B2"),(--):}...

`{:(" 3A"),("+25"),(--),(" B2"),(--):}`

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To solve the problem step by step, we need to analyze the equation given in the question: \(3A + 25 = B2\). 1. **Understanding the Equation**: - Here, \(3A\) represents a number formed by the digit 3 followed by the digit A. - \(B2\) represents a number formed by the digit B followed by the digit 2. - We need to find the values of A and B. 2. **Setting Up the Equation**: - The number \(3A\) can be expressed as \(30 + A\) (since A is the units digit). - The number \(B2\) can be expressed as \(10B + 2\) (since 2 is the units digit). - Therefore, we can rewrite the equation as: \[ 30 + A + 25 = 10B + 2 \] - Simplifying this gives: \[ 55 + A = 10B + 2 \] 3. **Rearranging the Equation**: - Rearranging the equation to isolate A gives: \[ A = 10B + 2 - 55 \] - This simplifies to: \[ A = 10B - 53 \] 4. **Finding Possible Values for A and B**: - Since A is a single digit (0 to 9), we need to find values of B such that \(10B - 53\) is a valid single digit. - Let's evaluate possible values of B: - If \(B = 6\): \[ A = 10(6) - 53 = 60 - 53 = 7 \] - If \(B = 7\): \[ A = 10(7) - 53 = 70 - 53 = 17 \quad (\text{not valid, since A must be a single digit}) \] - Therefore, the only valid solution is \(B = 6\) and \(A = 7\). 5. **Final Values**: - The values we found are: - \(A = 7\) - \(B = 6\) ### Summary of the Solution: - The values of A and B are: - \(A = 7\) - \(B = 6\)
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