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A certain particle carries '2.5 xx 10^(-...

A certain particle carries '2.5 xx 10^(-16) C' of static electric charge. Calculate the number of electrons present in it.

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In Millikans experiment, static electric charge on the oil drops has been obtained by shining X-rays. If the static electric charge on the oil drop is '-1.282 xx 10^(-18) C'. Calculate the number of electrons present on it.

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Knowledge Check

  • A negatively charged oil drop is prevented from falling under gravity by applying a vertical electric field 100 Vm^(-1) . If the mass of the drop is 1.6 xx 10^(-3)g , the number of electrons carried by the drop is (g = 10 ms^(-2))

    A
    `10^(18)`
    B
    `10^(15)`
    C
    `10^(6)`
    D
    `10^(12)`

  • An electron (mass = 9.1xx10^(-31) kg, charge = 1.6xx10^(-19) C) experiences no deflection if subjected to an electric field of 3.2xx10^5V//m , and a magnetic fields of 2.0xx10^(-3) Wb//m^2 . Both the fields are normal to the path of electron and to each other. If the electric field is removed, then the electron will revolve in an orbit of radius

    A
    45 m
    B
    4.5 m
    C
    0.45 m
    D
    0.045 m

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    The charges on a body is found to be -3.2xx10^(-19)C .Calculate the number of excess electrons present in the body that of proton .(Take e=-1.6xx10^(-19)C)

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    An electron is moving northward with a velocity 8.5 xx 10^(6) ms^(-1) in a magnetic field 2T, directed downward. Calculate the instantaneous force on the electron.

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