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The energy of the electron in the 'n^(th...

The energy of the electron in the 'n^(th) ' orbit of hydrogen atom is given as:
'E_n=(-1311.8)/n^2 k J m o l^(-1)'
What is the energy emitted per atom when an electron jumps from thịrd energy level to second energy level?

A

329.7 kJ'

B

3.03 xx 10^(-19)J'

C

182.2 kJ'

D

145.7 kJ'

Text Solution

Verified by Experts

The correct Answer is:
B
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The quantized energy of an electron in hydrogen atom for the n^(th) it level is given by E_n=(1.312)/n^2 xx 10^6 Jmol^(-1) , Calculate the energy required to remove the electron completely from an excited hydrogen atom when its quantized level, n=3 , (N_A=6.02 xx 10^(23) mol^(-1))

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Knowledge Check

  • The energy of electron in 3rd orbit of hydrogen atom is:

    A
    -1311.8 kJ mol^(-1)'
    B
    '-82.0 kJ mol^(-1)'
    C
    -145.7 kJ mol^(-1)'
    D
    -327.9 kJ mol^(-1)'

  • The de-Broglie wavelength lamda_(n) of the electron in the n^(th) orbit of hydrogen atom is

    A
    inversely proportional to n
    B
    proportional to `n^(2)`
    C
    proportional to n
    D
    inversely proportional to `n^(2)`

  • The energy possessed by an electron in the nth orbit, where n = alpha , is

    A
    infinity
    B
    zero
    C
    depends on the nucleus
    D
    None of these

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