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The compressibility of factor for an ide...

The compressibility of factor for an ideal gas is:

A

Unity at all temperatures

B

Unity at Boyle's temperature

C

Zero

D

Decreases with pressure

Text Solution

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The correct Answer is:
A
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The Compressibility factor for one mole of a van der Waal's gas at '0^circ C' and '100 atm' pressure is found to be '0.5 .' Assuming that the volume of gas molecule is negligible, calculate the van der Waal's constant 'a'?

At low pressure, the vander Waal's equation is written as (P + (a )/(V ^(2))) V = RT. The compressibility factor is then equal to

Knowledge Check

  • The gases which strictly follow the general equation (PV=nRT) are called ideal or perfect gases. Actuall there is no gas which is perfect or ideal. A real gas is one which actually exists, whether it obeys gas lav strictly or not. Under ordinary conditions, only those gases nearly behave as ideal or perfect which have ve low boiling points such as nitrogen, hydrogen etc. The most easily liquefiable and highly soluble gases such ammonia, carbon dioxide, sulphur dioxide show large deviations. A very convenient method of study in PV deviation of real gases from ideal behaviour is through a compressibility factor (Z), Z= (PV)/(nRT) i) Z=1, for ideal gases , ii) Z+1, for real gases At Boyle's temperature, compressibilitý factor Z for a real gas is:

    A
    `Z = 1`
    B
    Z = 0
    C
    `Z gt 1`
    D
    `Z lt 1`

  • Statement 1 : Compressibility factor (Z) for non-ideal gases can be greater than 1. Statement 2 : Non-ideal gases always exert higher pressure than ideal gases under identical condition expected.

    A
    Statement 1 is True, statement 2 is True, Statement 2 is Correct explanation for Statement 1.
    B
    Statement 1 is True, Statement 2 is True, Statement 2 is NOT a correct explanation for Statement 1.
    C
    Statement 1 is True, Statement 2 iş False.
    D
    Statement 1 is False, Statement 2 is True.

  • Assertion : Compressibility factor (Z) for non-ideal gases can be greater than 1. Reason : Non-ideal gases always exert higher pressure than ideal gases under identical conditions expected.

    A
    If both (A) and (R) are correct and (R) is the correct explanation of (A).
    B
    If both (A) and (R) are correct, but (R) is not the correct explanation of (A).
    C
    If (A) is correct, but (R) is incorrect.
    D
    If both (A) and (R) are incorrect.

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    The compressibility factor for definite amount of van der Waal's gas at 0^(@)C and 100 atm is found to be 0.5 . Assuming the volume of gas molecules negligible, the van der Waal's constant a for a gas is

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