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Calculate the enthalpy change on freezin...

Calculate the enthalpy change on freezing of `1.0 mol` of water at `10.0^@C` to ice at `-10.0^@C` . `Delta_( fus) H=6.03 kJ mol^(-1)` at `0^@C` .
`C_p[H_2 O(t)]=75.3 J mol^(-1) K^(-1)`
`C_p[H_2 O(s)]=36.8 J mol^(-1) K^(-1)`

Answer

Step by step text solution for Calculate the enthalpy change on freezing of 1.0 mol of water at 10.0^@C to ice at -10.0^@C . Delta_( fus) H=6.03 kJ mol^(-1) at 0^@C . C_p[H_2 O(t)]=75.3 J mol^(-1) K^(-1) C_p[H_2 O(s)]=36.8 J mol^(-1) K^(-1) by CHEMISTRY experts to help you in doubts & scoring excellent marks in Class 11 exams.

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Knowledge Check

  • The enthalpy change in freezing 1 g of water (Delta _fusion H = 6 .0 kJ mol^(-1) ) will be:- -6000.0 J , -333 J , 333.33J , 60.0 J

    A
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    B
    - 333 J'
    C
    333.33J' '
    D
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  • Calculate the equilibrium constant for a reaction at 400 K given that DeltaH^(@) = 308.3kJ mol^(-1) and Delta S = 0. 857 kJ K ^(-1) mol ^(-1) at 400 K.

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    `3.1959 xx 10 ^(4)`
    B
    `6.35 xx 10 ^(4)`
    C
    `9.25 xx 10 ^(4)`
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