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The value of 'Kc' of the reaction '3O2(g...

The value of 'K_c' of the reaction '3O_2(g) gives 2O_3(g)' is '2.0 x 10^(-50' at '25^circ C'. If the equilibrium concentration of 'O_2' in air át '25^circ C' is '1.6 x 10^(-2)', what is the concentration of 'O_3' ?

Answer

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The initial concentration of the first order reaction, N_2O_(5(g))to2NO_(2(g))+1/2O_(2(g)) was 1.24xx10^(-2)molL^(-1) .The concentration of N2O5 after ‘1’ hour was 0.20 x 10-2 mol L-1 Calculate the rate constant of the reaction at 300 K.

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Knowledge Check

  • The equilibrium constant for the reaction 2NO_(2)(g)iff2NO(g)+O_(2)(g)" is "2xx10^(-6)" at "185^(@)C . Then the equilibrium constant for the reaction, 4NO(g)+2O_(2)(g)rarr2NO_(2)(g) at the same temperature would be

    A
    a) 2.5x10^(-5)`
    B
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    C
    c)`2.5xx10^(11)`
    D
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  • For the reaction 2N_2O_5 (g) to 4NO_2 (g)+ O_2(g) If the concentration of NO_2 increases by 5.2 xx 10 ^(-3) M in 100 s then the rate of the reactions is :

    A
    ` 1.3 xx 10 ^(-5) Ms^(-1)`
    B
    ` 0.5 xx 10^(-4) Ms^(-1)`
    C
    ` 7.6 xx 10 ^(-4) Ms^(-1)`
    D
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  • When compared to the 'Delta G^circ' for the formation of 'Al_2 O_3', the 'Delta G^circ' for the formation of 'Cr_2 O_3' is Same unpredicted higher lower

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    Same
    B
    unpredicted
    C
    higher
    D
    lower
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