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The measured emf at 25^circ C for the ce...

The measured emf at `25^circ C` for the cell reaction. `Zn(s)+Cu^2 *(1.0 M)---Cu(s)+Zn^2 *(0.1 M)` is `1.3v` calculate `E0 cell` for the cell reaction.

Text Solution

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Using Nernst ệuation. `E_i in |^0=?` `` therefore 1.3 ~V=E_ ivll -0.0591/2 log 0.1/1.0 ``
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The measured EMF at 298 K for the cell reaction, Zn(s) + Cu^(2+)(1.0 M) rarr Cu(s) + Zn^(2+)(0.1M) is 1.13 V. Calculate E^(@) for the cell reaction.

The standard E.M.F. for the cell reaction: Zn(s) + Cu^(2+) (aq) - Zn^(2+) (aq) + (Cu) is 1.10 volts at 25^(@) C. The EMF. For the cell reaction when 0.01 M Cu^(2+) and 0.1 M Zn^(2+) solutions are used at 25^(@) C is:

Knowledge Check

  • For the redox reaction: Zn(s)+Cu^(2+) (0.1M) rarr Zn^(2+) (1M) + Cu(s) taking place in a cell, E_(cell)^(@) is 1.10V. E_(cell)^(@) for the cell will be [2.303(RT/F)=0.0591]

    A
    2.14 v
    B
    1.80 v
    C
    1.07 v
    D
    0.82 v

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