Which is the last element in the series of the actinoids? Write the electronic configuration of this element. Comment on the possible oxidation state of this element.

Explanation

Lawrencium (Lr) in the series of actinoids is the last element. Electronic configuration .=[(R) (n)]^(8 overline(8). .5 f^(14) 6 d^(1) 7 s^(2)=.
Possible oxidation state =+3, after the removal of one electron from 6 d and two from 7 s(t)+because 5 (f)^(14). is most stable]