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Which is the last element in the series ...

Which is the last element in the series of the actinoids? Write the electronic configuration of this element. Comment on the possible oxidation state of this element.

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Lawrencium (Lr) in the series of actinoids is the last element. Electronic configuration .=[(R) (n)]^(8 overline(8). .5 f^(14) 6 d^(1) 7 s^(2)=. Possible oxidation state =+3, after the removal of one electron from 6 d and two from 7 s(t)+because 5 (f)^(14). is most stable]
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Knowledge Check

  • The electronic configuration of four elements are:

    A
    `[Xe] 6s^1`
    B
    `[Xe] 4f^14, 5d^1, 6s^2`
    C
    `[Ar] 4s^2, 3d^10, 4p^5`
    D
    `[Ar]3d^7, 4s^2`

  • The electronic configuration of the element with maximum electron affinity is

    A
    a) `1s^(2),2s^(2),2p^(3)`
    B
    b)`1s^(2),2s^(2),2p^(5)`
    C
    c)`1s^(2),2s^(2),2p^(6),3s^(2),3p^(5)`
    D
    d)`1s^(2),2s^(2),2p^(6),3s^(2),3p^(3)`

  • The general electronic configuration of transition elements is:

    A
    `ns^(1-2) (n-1)d^(1-10)`
    B
    `ns^2 (n-1) d^10`
    C
    `(n-1) d^10 s^2`
    D
    `ns^2 np^5`

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